Three coherent beams of light get superposed on a point O.The intensity corresponding to each is I at point O.But phase of first wave is less than that of second by 2π/3 and greater than that of third by 2π/3.The resultant intensity at point O is
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OpenStudy (samigupta8):
@michele_laino
OpenStudy (samigupta8):
@ganeshie8
OpenStudy (rsadhvika):
Is the answer 0 ?
OpenStudy (samigupta8):
How did you get it?
OpenStudy (samigupta8):
Your ans is correct ..
Pls would you tell how u get that?
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OpenStudy (michele_laino):
I'm sorry, I'm not good with physical optics
OpenStudy (samigupta8):
:( I thought you would help...
But it's okay!!
OpenStudy (rsadhvika):
Take any two of the three waves
Would you agree that these two waves would be 120 degrees out of phase ?
OpenStudy (samigupta8):
Yep..i do..
OpenStudy (samigupta8):
Since they are meeting at a point so that means the angle subtended should be 2π then..
And we are given two angles already so third one will also b 2π/3
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OpenStudy (rsadhvika):
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OpenStudy (samigupta8):
Yep. .Then??
OpenStudy (rsadhvika):
Those are the phasors representing the 3 waves.
Add them vectorially, what do you get ?
OpenStudy (samigupta8):
0 vector...
OpenStudy (samigupta8):
One last thing...
Were i right in saying that the third angle is 2π/3 bcoz they are all meeting at single point O. And angle is 2π complete so angle is 2π/3...
Isn't it?
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