Three coherent beams of light get superposed on a point O.The intensity corresponding to each is I at point O.But phase of first wave is less than that of second by 2π/3 and greater than that of third by 2π/3.The resultant intensity at point O is
@michele_laino
@ganeshie8
Is the answer 0 ?
How did you get it?
Your ans is correct .. Pls would you tell how u get that?
I'm sorry, I'm not good with physical optics
:( I thought you would help... But it's okay!!
Take any two of the three waves Would you agree that these two waves would be 120 degrees out of phase ?
Yep..i do..
Since they are meeting at a point so that means the angle subtended should be 2π then.. And we are given two angles already so third one will also b 2π/3
|dw:1457627289627:dw|
Yep. .Then??
Those are the phasors representing the 3 waves. Add them vectorially, what do you get ?
0 vector...
One last thing... Were i right in saying that the third angle is 2π/3 bcoz they are all meeting at single point O. And angle is 2π complete so angle is 2π/3... Isn't it?
yes.. you are correct
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