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Physics 13 Online
OpenStudy (samigupta8):

Three coherent beams of light get superposed on a point O.The intensity corresponding to each is I at point O.But phase of first wave is less than that of second by 2π/3 and greater than that of third by 2π/3.The resultant intensity at point O is

OpenStudy (samigupta8):

@michele_laino

OpenStudy (samigupta8):

@ganeshie8

OpenStudy (rsadhvika):

Is the answer 0 ?

OpenStudy (samigupta8):

How did you get it?

OpenStudy (samigupta8):

Your ans is correct .. Pls would you tell how u get that?

OpenStudy (michele_laino):

I'm sorry, I'm not good with physical optics

OpenStudy (samigupta8):

:( I thought you would help... But it's okay!!

OpenStudy (rsadhvika):

Take any two of the three waves Would you agree that these two waves would be 120 degrees out of phase ?

OpenStudy (samigupta8):

Yep..i do..

OpenStudy (samigupta8):

Since they are meeting at a point so that means the angle subtended should be 2π then.. And we are given two angles already so third one will also b 2π/3

OpenStudy (rsadhvika):

|dw:1457627289627:dw|

OpenStudy (samigupta8):

Yep. .Then??

OpenStudy (rsadhvika):

Those are the phasors representing the 3 waves. Add them vectorially, what do you get ?

OpenStudy (samigupta8):

0 vector...

OpenStudy (samigupta8):

One last thing... Were i right in saying that the third angle is 2π/3 bcoz they are all meeting at single point O. And angle is 2π complete so angle is 2π/3... Isn't it?

OpenStudy (priyar):

yes.. you are correct

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