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Simplify 13 over the quantity of negative 3 plus 2i.
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\[\frac{ 13 }{ 3+2i }\]
the 3 is suppose to be negative but I got -3+2i @ganeshie8 am I right? \[\frac{ 13\left( -3+2i \right) }{ -3+2i \left( -3-2i \right)} = \frac{ -39+26i }{ 13 }= -3+2i\]
You mean \(\displaystyle \frac{ 13\left( -3+2i \right) }{\color{red}{(} -3+2i \color{red}{)}\left( -3-2i \right)} = \frac{ -39+26i }{ 13 }= -3+2i\)
yes, what you did is correct
just don't leave those parenthesis, so that we can correctly see what you multiply by... for other than this, that was very well done! Good Job!
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