Linear algebra question! Will be posted below.

Take note: R = 16.

Question

Linear algebra question! Will be posted below.

Take note: R = 16.

mortonsalt · Answer

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mortonsalt · Answer

I've gotten the equations for loop 1, 2, and 3. They are (respectively): 

$$6i_1 - 6i_3 -v=8$$
$$9i_2-8i_3=3$$
$$-6i_1-8i_2+19i_3-3i_4=0$$

mortonsalt · Answer

I think that the equation for loop 4 is, although I'm not entirely sure.
$$-3i_3 +19i_4 -v=0$$

mortonsalt · Answer

The question asks for the voltage drop across the 3 Ohm resistor and the current through the 6 Ohm resistor. Thanks!

jigglypuff314 · Answer

This is out of my league, sorry. Can someone else help? @mathmale @freckles @jim_thompson5910 @SolomonZelman @zepdrix

mortonsalt · Answer

@jigglypuff314 No worries! Thank you though. :)

solomonzelman · Answer

I am ridicuously bad at circuits. Especially reading from these diagrams, (although once I set a system I, like most people) can do whatever I desire to it ... )

solomonzelman · Answer

So if you want me to check the setup I am not of any help:(

mortonsalt · Answer

@SolomonZelman, that's quite alright. Thank you! :)

anonymous · Answer

I'm also a newb to this topic, but I can try c:

Loop 2 and 3 seems right.

You have to apply Supermesh (loops 1 & 4) at the current source.
If we will do that, it will be:

$ 6i_1-6i_3-3i_3+ 16i_4 + 3i_4=8\ 6i_1-9i_3+19i_4=8$ 

Now, we have four variables so it means we need 4 equations.
Let's look at the distribution of the current source wrt ground:
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