ct all combinations of the following numbers that when added together would be rational.
−6, 32√, 23, 13, 7√
Question 6 options:
−6 and 23
32√ and 23
23 and 13
13 and 7√
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OpenStudy (anonymous):
NO GUESS OR I THINK I NEED A WALK THROUGH OR DIRECT ANSWER
OpenStudy (kayders1997):
It's hard to read what is going on with the square roots and everything, can you rewrite it?
OpenStudy (anonymous):
oh ya sure
OpenStudy (anonymous):
\[its \sqrt{32} and \sqrt{7}\]
OpenStudy (kayders1997):
okay
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OpenStudy (kayders1997):
first of all do you know what a rational number is
OpenStudy (anonymous):
oh shoot yea i know a rational number is and i need to fix the choices hang on
OpenStudy (anonymous):
\[-6, 2\sqrt{3}, 2/3, 1/3, and \sqrt{7}\]
OpenStudy (anonymous):
so the 23 and the 13 are fractions and 32 is 2squareroot3
OpenStudy (kayders1997):
okay
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OpenStudy (kayders1997):
so those are the answer choice so it says you need to combine so you need to add those values together, what do you get when you add the first choices
OpenStudy (kayders1997):
so -6+2/3 I think your telling me based on the changes you said
OpenStudy (anonymous):
yes and it is -16/3 or -5 1/3
OpenStudy (kayders1997):
Yes does that have a end point (integer), or a repeating decimal?
OpenStudy (kayders1997):
I should have said whole number my bad not end point
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OpenStudy (kayders1997):
do you understand what I am saying?
OpenStudy (anonymous):
so either integer or repeating decimal
OpenStudy (kayders1997):
Yes
OpenStudy (anonymous):
the decimal is repeating 5.3 reapeating
OpenStudy (kayders1997):
yes it is so that would be considered a combination that is rational
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OpenStudy (kayders1997):
There is one more here
OpenStudy (anonymous):
ok
OpenStudy (kayders1997):
Do you think the square roots will give you an integer or repeating decimal?
OpenStudy (anonymous):
Yes?
OpenStudy (kayders1997):
most likely not unless you have a perfect square
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OpenStudy (kayders1997):
Think about the 3rd function if you are adding 2/3+1/3 what do you get
OpenStudy (anonymous):
1
OpenStudy (kayders1997):
Yes is that an integer?
OpenStudy (anonymous):
yes
OpenStudy (kayders1997):
Yep so those are your two answers :)
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OpenStudy (anonymous):
hey kayder can u help on my word problem @kayders1997