Find the zeros of the polynomial function. f(x) = x2 – 12x + 20 4, 5 2, 10 –4, –5 –2, –10
You posted this earlier and I responded in depth. Why are y ou posting this question again? I'm not eager to repeat what I typed earlier in an effort to help you.
Just set the problem equal to 0 and solve for x ^-^
Do you know how to factor? >_>
x^2 -12x+20=0 x^2-12x=-20 now once i get to this point what should i do
The quadratic formula also works.\[f(x)=ax^{2}+bx-c\rightarrow x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]
Oh, you're completing the square?
Keep this equation as given: x^2 -12x+20=0 It does not help to move that 20 to the right side.
Yes, what @mathmale said... completing the square doesn't help you find the zeros. I believe it only helps you find the vertex form of a quadratic function
As I shared with you earlier, methods of solving this equation include: 1. graphing 2. completing the square 3. factoring 4. quadratic formula 5. factoring by grouping Please identify the approach that YOU want to use.
But this is a simple question. All you need to do is factor to find the 0's.
Yes: that'd be the easiest approach. But learning to use other approaches would be helpful as well.
I meant to send that in reply to kitti, my apologies :P
xD Well, the quadratic formula also works as the "long way round" when you can't factor or get stuck doing that... ^-^
Oh, so you CAN use completing the squ- wait yeah I'm dumb lol Do you know how to continue solving using complete the square?
@ayonnaleflore: Your input, please? Questions? Comments?
Yes, completing the square would definitely "work" here. But: factoring would be the fastest method.
no i dont know how to continue by completing the square @kittiwitti1
Then please cross that off the list. Which other method would you like to use?
The link I posted helps with completing the square, but you can also use other options, as we have said before ☻
factoring by grouping but im not sure how to do that
As I shared with you earlier, methods of solving this equation include: 1. graphing 2. completing the square 3. factoring 4. quadratic formula 5. factoring by grouping Please identify the approach that YOU want to use.
so how would i start it off???
I don't think you can factor by grouping when there's a trinomial (three terms). I thought it required four terms.. :\
wait doesn't it need four terms to factor by grouping
lol yeah, my question exactly xD
ok so how about factoring??
You can "make" four terms during factoring by grouping. Separate -12x into two parts that combine to produce -12x. Factor by grouping. Or, if you prefer, just factor. How would you do that? Hint: What are possible factors of 20?
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Oh right. I suppose you could do that
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