A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2
use one of the equations for motion under gravity t = 5 , g = 9.81, s (distance) is to be found s = (1/2) g t^2 To find depth of the well subtract 100 from s.
so what is s/how do I get s
replace g by 9.81 and t by 5 in the above equation and work it out
(1/2)9.81(5^2)
yes correct so far now do the multiplication
1/2 * 9.81 * 5^2
122.625?
yes that is the distance from top of the tower to the bottom of the well, So to find the depth of the well you subtract 100 m from it.
22.625
thats correct
OK?
22.5 meters 50.7 meters 100 meters 110 meters 152.45 meters
I think the top one im I right?
yes thats the closest
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