A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2
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OpenStudy (welshfella):
use one of the equations for motion under gravity
t = 5 , g = 9.81, s (distance) is to be found
s = (1/2) g t^2
To find depth of the well subtract 100 from s.
OpenStudy (badsheep):
so what is s/how do I get s
OpenStudy (welshfella):
replace g by 9.81 and t by 5 in the above equation and work it out
OpenStudy (badsheep):
(1/2)9.81(5^2)
OpenStudy (welshfella):
yes correct so far
now do the multiplication
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OpenStudy (welshfella):
1/2 * 9.81 * 5^2
OpenStudy (badsheep):
122.625?
OpenStudy (welshfella):
yes
that is the distance from top of the tower to the bottom of the well, So to find the depth of the well you subtract 100 m from it.
OpenStudy (badsheep):
22.625
OpenStudy (welshfella):
thats correct
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