Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (badsheep):

A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2

OpenStudy (welshfella):

use one of the equations for motion under gravity t = 5 , g = 9.81, s (distance) is to be found s = (1/2) g t^2 To find depth of the well subtract 100 from s.

OpenStudy (badsheep):

so what is s/how do I get s

OpenStudy (welshfella):

replace g by 9.81 and t by 5 in the above equation and work it out

OpenStudy (badsheep):

(1/2)9.81(5^2)

OpenStudy (welshfella):

yes correct so far now do the multiplication

OpenStudy (welshfella):

1/2 * 9.81 * 5^2

OpenStudy (badsheep):

122.625?

OpenStudy (welshfella):

yes that is the distance from top of the tower to the bottom of the well, So to find the depth of the well you subtract 100 m from it.

OpenStudy (badsheep):

22.625

OpenStudy (welshfella):

thats correct

OpenStudy (welshfella):

OK?

OpenStudy (badsheep):

22.5 meters 50.7 meters 100 meters 110 meters 152.45 meters

OpenStudy (badsheep):

I think the top one im I right?

OpenStudy (welshfella):

yes thats the closest

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!