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Mathematics 12 Online
OpenStudy (calculusxy):

How to multiply this expression?

OpenStudy (calculusxy):

\[\huge 4\pi(4.096\times 10^{13})\]

OpenStudy (calculusxy):

@phi

OpenStudy (anonymous):

YOu're saying you need help on it or what?

OpenStudy (calculusxy):

Yes I need help on it

OpenStudy (calculusxy):

@Nnesha Can you please help me?

OpenStudy (anonymous):

Got about 5200 you need me to explain it or just give you the answer?

OpenStudy (anonymous):

@calculusxy Just multiply 4*4.096. Then leave it in terms of pi and 10^13

OpenStudy (phi):

the 4 * 4096 are powers of 2. Some computer types would know it is 16384 or with the decimal 16.384 multiplying by pi is harder

OpenStudy (calculusxy):

(16.384 \(\times\) \(10^{13}\))\(\pi\)

OpenStudy (phi):

then make the 16.384 "smaller" to 1.6384 and compensate by making the exponent bigger by 1, from 13 to 14

OpenStudy (calculusxy):

But my teacher said for me to evaluate it even with the \(\pi\). I mean I can type it up in a calculator and then do it, but I have this thing that says \(e+\) which i have no idea about

OpenStudy (phi):

are you allowed to use a calculator , but don't know what the answer means ?

OpenStudy (calculusxy):

yes.

OpenStudy (calculusxy):

I get this when I type it up in a calculator.

OpenStudy (phi):

so far you have \[ \pi(1.6384 \times 10^{14}) \\ \pi \cdot 1.6384e14 \]

OpenStudy (phi):

you will get an answer of about 5.0e14

OpenStudy (calculusxy):

so how do I write it down in scientific notation?

OpenStudy (calculusxy):

here is the actual problem (look at part a) from which i am doing my work for

OpenStudy (phi):

you would type in pi * 4 * 4.096 EXP 13 =

OpenStudy (calculusxy):

So my answer would be what?

OpenStudy (phi):

try doing that on your calculator

OpenStudy (calculusxy):

I did type it in and then that's what i got in the screenshot with the e+14

OpenStudy (calculusxy):

OpenStudy (phi):

yes, the "e+14" means exponent. It is short for \(10^{14}\)

OpenStudy (calculusxy):

so the problem wants for me to approximate it. what should i approximate it to?

OpenStudy (phi):

you could also type in 4*pi*( 6.4 EXP 6) square (whatever button squares it)

OpenStudy (phi):

the input 6.4e6 only has 1 decimal. I would round the answer to two decimals, so 5.15e14

OpenStudy (calculusxy):

okay! so my answer would be \(5.15 \times 10^{14}\)

OpenStudy (phi):

yes, and probably add m^2 (for square meters)

OpenStudy (calculusxy):

okay can you help me with the remaining two parts of the question please?

OpenStudy (calculusxy):

for part b-- i know that 70% = 0.7 (which in scientific notation would be \(7 \times 10^{-1}\). so do i do \(\large \frac{5.15 \times 10^{14}}{7 \times 10^{-1}}\)

OpenStudy (phi):

ok, but you don't divide. if you wanted 70% of 100 you would do 0.7 * 100 = 70 (not divide) and though you could change 0.7 to 7e(-1) I would not bother I would do 0.7*5.15e14 =

OpenStudy (calculusxy):

but would i multiply \(7 \times 10^{-1}\) with \(5.15 \times 10^{14}\) then?

OpenStudy (phi):

you could, but that is more work. First, do it the way I suggested: 0.7*5.15e14 = what do you get ?

OpenStudy (calculusxy):

3.605 x \(10^{14}\)

OpenStudy (calculusxy):

oh wow that is the answer isn't it?

OpenStudy (phi):

yes. now do it the other way. You should get the same number.

OpenStudy (calculusxy):

yeah i tried and i got the same answer :) moving on to part c

OpenStudy (calculusxy):

so for the last question, it's basically asking to find the volume of a sphere right?

OpenStudy (phi):

no, something simpler. It's a "rough" calculation, so just imagine you had a region with a bottom area of 3.6e15 m^2 and a height of 3795 m and use Volume of a prism = area_of_base * height

OpenStudy (calculusxy):

so would i do in here \[\large (3795)(3.605 \times 10^{14})\]

OpenStudy (phi):

yes

OpenStudy (calculusxy):

okay

OpenStudy (calculusxy):

give me one more minute

OpenStudy (calculusxy):

i got 1.3680975 \(\times\) \(10^{18}\)

OpenStudy (phi):

yes, with units m^3 (cubic meters)

OpenStudy (calculusxy):

okay thank you so much!!!! :)

OpenStudy (phi):

you should probably round your final answer to 1.37e18 m^3

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