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Please help. i tried them all i cant figure it out. 2x^2-12=116 A i got 4 B i got 52 C i got 244 D i got 1012
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2x^2 = 116 + 12 2x^2 = 128 x^2 = 128/2 x^2 = 64
Now you need to find the 2 square roots of 64 and thats your answer
b
?? does 4 * 4 = 64??
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oh 8*8
so 8 is one root what is the other?
-8
yes
thanks :))
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yw
Another way to do it (a little bit harder than what @welshfella did): Quadratics \(\large 2x^2 - 12 = 116\) \(2x^2 - 128 = 0\) \(2(x^2 - 64) = 0\) \(2(x-8)(x+8) = 0\) Solve for what \(x\) is so that it can make the equation be 0 (or find the roots) \(2x - 16 = 0\) \(x = 8\) \(x + 8 = 0\) \(x = -8\) Two roots (or x-values): 8, -8
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