Question

Factor a^12-b^6

Answer 1

(a^2-b)(a^2+b)

Answer 2

yes, is a difference of squares, so, use that :)

Answer 3

Not quite, rewrite it as:
\[a ^{12}-b^6 \iff (a^6)^2-(b^3)^2\]

Answer 4

Oh okaythanks ;)

Answer 5

@AloneS. Is there a final answer for this problem?

Answer 6

@Directrix I think i have to look..i can't fine my hw

Answer 7

Oh my Gosh my techer corrected it and it was wrong -.- I put (a2-b)(a2+b) but the right answer was (a^6-b^3 )(a^6+b^3)
It was wrong @Directrix

Answer 8

The teacher needs to look again at this answer: (a^6-b^3 )(a^6+b^3)

That will factor again as the difference and sum of two cubes.

Regardless, >>(a^2-b)(a^2+b) is not correct. It multiplies back to a^4 - b^2 which is not the same as the expression to be factored.



@AloneS.

Answer 9

Yeah i'll tell him on monday ..see what he says x3