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Mathematics 19 Online
OpenStudy (anonymous):

Use ΔABC shown below to answer the question that follows: Triangle ABC with segment AD drawn from vertex A and intersecting side BC. Which of the following must be given to prove that ΔABC is similar to ΔDBA? (6 points) Segment AD is an altitude of ΔABC. Segment CB is a hypotenuse. Segment CA is shorter than segment BA. Angle C is congruent to itself.

OpenStudy (anonymous):

OpenStudy (anonymous):

i know it is not the first one

OpenStudy (jingle535):

So this goes back to what we had before, the ways to prove triangle similarity, one of those gives you the needed information to prove them similar

OpenStudy (anonymous):

SAS?

OpenStudy (jingle535):

How do you know its not the first one?

OpenStudy (anonymous):

it isnt needed to prove that

OpenStudy (jingle535):

How do you know?

OpenStudy (anonymous):

nevermind i just looked at the definition of an altitude. We need to know that the smaller triangle has a 90 degree angle

OpenStudy (jingle535):

Yes and an altitude gives you this|dw:1457800315320:dw|

OpenStudy (anonymous):

i was used to perpendicular

OpenStudy (anonymous):

:P

OpenStudy (anonymous):

so it is the first one

OpenStudy (anonymous):

I have another question

OpenStudy (jingle535):

Yep :)

OpenStudy (anonymous):

Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points) By the cross product property, AB2 = BC multiplied by BD. By the cross product property, AC2 = BC multiplied by BD. By the cross product property, AC2 = BC multiplied by AD. By the cross product property, AB2 = BC multiplied by AD.

OpenStudy (jingle535):

New sheet please, because some of these I might not be able to get

OpenStudy (anonymous):

ok

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