Use ΔABC shown below to answer the question that follows: Triangle ABC with segment AD drawn from vertex A and intersecting side BC. Which of the following must be given to prove that ΔABC is similar to ΔDBA? (6 points) Segment AD is an altitude of ΔABC. Segment CB is a hypotenuse. Segment CA is shorter than segment BA. Angle C is congruent to itself.
i know it is not the first one
So this goes back to what we had before, the ways to prove triangle similarity, one of those gives you the needed information to prove them similar
SAS?
How do you know its not the first one?
it isnt needed to prove that
How do you know?
nevermind i just looked at the definition of an altitude. We need to know that the smaller triangle has a 90 degree angle
Yes and an altitude gives you this|dw:1457800315320:dw|
i was used to perpendicular
:P
so it is the first one
I have another question
Yep :)
Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points) By the cross product property, AB2 = BC multiplied by BD. By the cross product property, AC2 = BC multiplied by BD. By the cross product property, AC2 = BC multiplied by AD. By the cross product property, AB2 = BC multiplied by AD.
New sheet please, because some of these I might not be able to get
ok
Join our real-time social learning platform and learn together with your friends!