Question

If I could get help not only solving this but understanding it that would be amazing! Thanks!
How much heat is required to vaporize 1.5 kg of liquid water at its boiling point (Hv = 2.26 × 106 J/kg)?
6.6 × 10^-7 J

-1.5 × 106 J

1.5 × 106 J

3.4 × 106 J

Answer 1

@agent0smith

Answer 2

But you had a question exactly like this a day ago. It's just Q=mL again. L is the heat of vaporization, m is mass.

Answer 3

so 3.34 option D