Solve the following equation by transforming it into a perfect square trinomial.

x2 – 14x = 15

{–15, 29}

{57, 71}

{–22, 36}

{–1, 15}

Question

Solve the following equation by transforming it into a perfect square trinomial.

 

        x2 – 14x = 15


   

{–15, 29}
 
   
{57, 71}

 
   

{–22, 36}
 
   

{–1, 15}

er.mohd.amir · Answer

for perfect sq
a*a+b*b+-2a*b sue this

er.mohd.amir · Answer

x*x-14x-15=0
x*x-2*x*7+7*7-7*7-15=0

calculusxy · Answer

Make $x^2 - 14x = 15$ into a quadratic equation in standard form ($ax^2 + bx + c = 0$).

calculusxy · Answer

You can bring over the 15 from the right side of the equal sign to the left side by subtracting it form both sides. 
$x^2 - 14x = 15$
$x^2 - 14x - 15 = 15 - 15$
Then you will see that on the right side, it will eventually equal to 0. 
$\color{green}{x^2 - 14x - 15 = 0}$

calculusxy · Answer

Finally use any methods, such as factoring, completing the square, quadratic formula, etc.

calculusxy · Answer

@ayonnaleflore Are you still online and solving this problem? If you don't reply, then I can't help you.