Diff EQ. Linearly independent? Where do they get the value x=0, to plug in and get the expression equal to 1?
They are using this rule: Given two functions \(f(x)\) and \(g(x)\) that are differentiable on some interval \(I\). (1) If \(W(f,g)(x_0)\ne0\) for some \(x_0\) in \(I\), then \(f(x)\) and \(g(x)\) are linearly independent on the interval \(I\). (2) If \(f(x)\) and \(g(x)\) are linearly dependent on \(I\) then \(W(f,g)(x) = 0\) for all \(x\) in the interval \(I\). They made the conclusion by choosing \(x_0=0\) and applying rule (1) above.
If you want to learn more there is a great site called Pauls Online Math Notes. Here is the relevant section in that site that might help you further understand this: http://tutorial.math.lamar.edu/Classes/DE/Wronskian.aspx
Thanks, I missed that.
yw :)
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