Question

FAN AND MEDAL AND TESTIMONY


Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share?

Answer 1

Oooo trig xD

Answer 2

Lmao I hate it, this is the final test of module 7 that I am working on

Answer 3

Well first determine the ratio for sine...what is the ratio?

Answer 4

5:12

Answer 5

Actually the ratio of sine is....

\(\Huge{\sin(x)=\frac{opposite}{hypotenuse}}\) In which we would need to find the hypotenuse so we would use the Pythagorean Theorem....

\(\Huge{a^{2}+b^{2}=c^{2}}\) Input....

\(\Huge\color{purple}{12^{2}+5^{2}=c^{2}}\) Simplify the exponent....

\(\Huge\color{green}{144+25=c^{2}}\) Add...

\(\Huge\color{orange}{169=c^{2}}\) We have to find the square root of \(\large{169}\)

\(\Huge\color{red}{\sqrt{169}=c}\) What would \(\large{c}\) be?

Answer 6

13

Answer 7

Correct ^^ So the hypotenuse is 13 and the opposite side is 5 so we would input this into the sin ratio....

\(\Huge{\sin(x)=\frac{5}{12}}\) Now since \(\large{x}\) is with sin we would invert....

\(\Huge{x=\sin^{-1}(\color{red}{\frac{5}{12}})}\)

Note: When inputting into the calculator make sure to have your cal sent into degree mode.

So what would x be?

Answer 8

oooo mean 13* not 12

Answer 9

I got 24.62

Answer 10

If thats correct haha

Answer 11

That is correct ^^

Answer 12

Now since we know of each side of the triangle we can find the cosine....now what is the ratio for cosine??

Answer 13

Ooooo hold on...

Answer 14

I forgot it was suppose to be...

\(\Huge{x=\sin^{-1}(\frac{5}{13})}\) but if it were 12 it would be correct but this is the equation for x.....so what would be the answer?

Answer 15

Oh okay one sec, ill plug both the cos and sin in

Answer 16

Alrighty ^^

Answer 17

Sin 22.61 and cos 22.61

Answer 18

Sin is right but cos is incorrect....The ratio for cos is...

\(\Huge{y=\cos^{-1}(\frac{5}{13})}\)

Answer 19

Were you able to find cos y ?

Answer 20

Sorry! My internet went out, I got 67.38

Answer 21

But how do the cos and sin share a relationship?