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Algebra 20 Online
OpenStudy (drummergirl7):

Oh my god PLEASE HELP ME IM BEGGING I'll medal and fan plz help me

OpenStudy (drummergirl7):

Which value for X makes the sentence true? 1/6 + X = 1/4 A.1/5 B.1/12 C.1/2 D.5/12

OpenStudy (anonymous):

\[\frac{1}{6}+x=\frac{1}{4}\]?

OpenStudy (sasquat):

So for this question all you got do is treat it like an equation: x=1/4-1/6

OpenStudy (anonymous):

or perhaps \[\frac{1}{6+x}=\frac{1}{4}\]?

OpenStudy (sasquat):

then you gotta find a common denominator

OpenStudy (anonymous):

if it is the first one, go with @sasquat subtract \(\frac{1}{6}\) from \(\frac{1}{4}\) i.e. compute \[\huge\frac{1}{4}-\frac{1}{6}\] and you are done

OpenStudy (mathmale):

then you gotta find a common denominator. What is the smallest denominator that is divisible by both 4 and 6 with no remainder?

OpenStudy (mathmale):

Can you divide 8 by 4? is there a remainder? Can you divide 8 by 6? is there a remainder? If you have a remainder, drop 8. What's a logical next higher number to use? Actually, both 4 and 6 can be factored. Factoring them and then choosing all the separate factors would help you identify the LCD here. Hint: 2*2=4, so 4 factors into (2)(2). 2*3=?, so ................. ?

OpenStudy (anonymous):

x= 1/12

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