Question

A rock dropped from an unknown height hits the ground below with a velocity of 15.0 m/s. From what height was the rock dropped?

Answer 1

the question is a case of motion under gravity.

step 1 is taking sign convention . I take upward direction positive & downward direction negative.
so,

a=-g
u=initial velocity=0
v=final velocity=15 m/s
h=height from which the ball was dropped.

Answer 2

use the equation
\(v^2=u^2-2gh\)

Answer 3

i have given u all the values. substitute the values in the equation & gt ur answer .

Answer 4

Thank you!

Answer 5

yw :)