A rock dropped from an unknown height hits the ground below with a velocity of 15.0 m/s. From what height was the rock dropped?

Question

jiteshmeghwal9 · Answer

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jiteshmeghwal9 · Answer

the question is a case of motion under gravity.

step 1 is taking sign convention . I take upward direction positive & downward direction negative.
so,

a=-g
u=initial velocity=0
v=final velocity=15 m/s
h=height from which the ball was dropped.

jiteshmeghwal9 · Answer

use the equation
$v^2=u^2-2gh$

jiteshmeghwal9 · Answer

i have given u all the values. substitute the values in the equation & gt ur answer .

anonymous · Answer

Thank you!

jiteshmeghwal9 · Answer

yw :)