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OpenStudy (anonymous):
Can someone help with this derivative question?
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OpenStudy (anonymous):
OpenStudy (phi):
what is the derivative of [ f(x) ]^2 ?
OpenStudy (anonymous):
2x, no?
OpenStudy (anonymous):
There really isn't a function given, so I'm just getting the derivative of x^2 there,
OpenStudy (anonymous):
@phi
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OpenStudy (phi):
the rule is
\[ \frac{d}{dx} u^2 = 2 u \ \frac{du}{dx}\]
OpenStudy (phi):
in this case, u is f(x)
OpenStudy (phi):
what do you get ?
OpenStudy (anonymous):
16
OpenStudy (phi):
before you put in any numbers, what is the expression you get ?
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OpenStudy (anonymous):
Is that correct? I just plugged in the derivative of f(x) from the graph an then multiplied it by 2.
OpenStudy (phi):
first, use this rule with f(x) instead of u
\[ \frac{d}{dx} u^2 = 2 u \ \frac{du}{dx} \]
what expression do you get ?
OpenStudy (anonymous):
2f(x)
OpenStudy (phi):
you left off the df(x)/dx (also written f'(x) )
OpenStudy (anonymous):
2f(x) f'(x) ohh! Duh duh duh
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OpenStudy (anonymous):
Wait I meant
OpenStudy (phi):
if you had
\[ \frac{d}{dx} x^2 = 2 x \frac{dx}{dx} = x^2 \]
but for f(x) you get
\[ \frac{d}{dx} f(x)^2 = 2 f(x)\frac{df(x)}{dx} = 2 f(x) f'(x) \]
OpenStudy (phi):
* 2x on the first line not x^2
OpenStudy (anonymous):
Thank you phi! 96
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