Can someone help with this derivative question?
what is the derivative of [ f(x) ]^2 ?
2x, no?
There really isn't a function given, so I'm just getting the derivative of x^2 there,
@phi
the rule is \[ \frac{d}{dx} u^2 = 2 u \ \frac{du}{dx}\]
in this case, u is f(x)
what do you get ?
16
before you put in any numbers, what is the expression you get ?
Is that correct? I just plugged in the derivative of f(x) from the graph an then multiplied it by 2.
first, use this rule with f(x) instead of u \[ \frac{d}{dx} u^2 = 2 u \ \frac{du}{dx} \] what expression do you get ?
2f(x)
you left off the df(x)/dx (also written f'(x) )
2f(x) f'(x) ohh! Duh duh duh
Wait I meant
if you had \[ \frac{d}{dx} x^2 = 2 x \frac{dx}{dx} = x^2 \] but for f(x) you get \[ \frac{d}{dx} f(x)^2 = 2 f(x)\frac{df(x)}{dx} = 2 f(x) f'(x) \]
* 2x on the first line not x^2
Thank you phi! 96
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