Question

Please someone help ill fan and medal please someone. :( http://prntscr.com/aff05f

Answer 1

Part A and B are good, part C though

Let's factor it out first

Answer 2

I'm not sure if they're asking for the coefficient before or after? If it's before you're right

If it's after, we would first distribute the 9 into the 7+2x

Answer 3

I do suppose you are right though, since that is in factored out form

Answer 4

Yeah, lets see it
Good job on the first btw

Answer 5

So for part A, they want you to write down the formula, but with the numbers plugged in. How would that look?

Answer 6

Sure

Part A is just plugging in without answering
Part B is actually answering

Answer 7

It's alright. Remember, Part A has no calculations involved. We're just taking the formula they gave us and rewriting it, but we're just changing the r and s to the values they gave us

Answer 8

\[3.14((r)(s)+(r^2))\]Thats what we have. Can you rewrite that and replace the R and S with the given values for me?

Answer 9

Correct! That's Part A.

Now let's do Part B

Answer 10

So let's do what's in the parenthesis first

\[(5)(3)+(3^2)\]

Let's find (5)(3), then let's find (3^2), then we can add those two answers together

Answer 11

I like all of that, but recheck if 15 + 9 really is 21

Answer 12

Oh, I don't think you are. Everyone does it
I remember writing that 2+3=2 on a Calculus Test lol

But yeah, after you do 24, you got the rest right

Answer 13

Yep, just re calculate 24x3.14 since you had to change the 21 to a 24

Answer 14

Looks good!

Answer 15

Do you see any ways in which we can make some equivalent expressions?

Answer 16

So what do you see? lol

Answer 17

Technically, it is! I like that idea

Answer 18

I'm not sure if your teacher will accept that, but that is a different and equivalent expression.

They want one more expression in Part A

Answer 19

Yep, looks good

Answer 20

Yeah, that's why I was thinking of something different. I'm not sure if those equivalents will roll over to part B.

You could say addition works no matter the order, but I don't think that's valid enough

Answer 21

Let's distribute
So, we have have \[6(m+2+7m)\]

\[(6)(m) = ?\]
\[(6)(2) = ?\]
\[(6)(7m) = ?\]

Answer 22

When distributing, let's take this expression for example, we multiply the 6 (The number outside the parenthesis) by everything that's in the parenthesis

Answer 23

Right

\[(6)(m)\] would simply be \[6m\]

What would \[(6)(7m)\] be? This one is a combination of the first two

Answer 24

Right do 6x7 first, then add the m on the end after calculating

Answer 25

Alright, so we started with

\[6(m+2+7m)\]
When just distributed the 6 into everything, giving us

\[6m+12+42m\] That's our first example

Answer 26

Now for the second, let's combine like terms

\[6m + 12 +42m\]

Does this expression have any like-terms?

Answer 27

The 6m and the 42m do, because they both are a number that ends in m

Because of this, we can add these together

Answer 28

We would do \[42m+6m = ?\]

Answer 29

We can then add that to the 12 to get

\[12+48m\]

As our second expression

Answer 30

Yes

Answer 31

Let's use the first expression we made, do you have that one?

Answer 32

Ok.

Factor out a 6 for me, then

Answer 33

So, let's take a 6 out of that equation

6(6m + 12 + 42m)

Now divide everything in the parenthesis by 6 (since you took a 6 out)

Answer 34

6m/6
12/6
42m/6

Answer 35

Sure, lets say I have

2(x + 5 + 3x)

After blah blah, we get 2x+10+6x

Now we factor out a 2

2(2x+10 +6x)

We then divide by 2

2x/2 = 2
10/2 = 5
6x/2 = 3x

Those 3 answers are in the original, making the equivalent true

Answer 36

2x/2 = x

I mean

Answer 37

I don't do direct answers, especially with moderators question floating