Help?
For the first one, it could be a or d. I don't know what n starts on so I don't know.
N is the numbers they provide like -2... thats a1
I was thinking A or D as well. I'm torn because we can only choose one, and only one is correct.
If the index starts at 0, i.e. \(a_0,a_1,a_2,\dots\), then it is pretty clear that it is a. If the index starts at 1, i.e. \(a_1,a_2,a_3,\dots\), then it is pretty clear that it is d. b and c does not make sense since if you increase n by one \(a_n\) would also increase by one. In other words, for b and c, \(a_{n+1}-a_n=1\).
Okay so you're thinking its A? Okay cool how about the next two?
@thomas5267
How do you write down a sequence? Does the index start from 0 or 1?
It starts with 1.
For the write down the explicit definition for the sequence question it should be D.
Yeperonni! thank you!
For the sum of first 10 terms question, use the formula for arithmetic series.
I got C how does that sound?
You missed the factor of 2?
Hang on.
Okay im confused. How do you set this up?
Using \(\displaystyle S_n=\frac{n(a_1+a_n)}{2}\).
S10=10(41+an)/2 ???
That's the general formula. In this case, \(\displaystyle S_{10}=\frac{10(a_1+a_{10})}{2}\)
Ahh okay so B?
Yep.
mm wonder why its not D or C?
Just add the 10 terms manually and you will understand why it is not C or D. XD
AHAHAH oh wow.. missed the sum part. Okay thanks!
For the geometric series, use the formula again. \[ \sum_{k=0}^nar^k=a\frac{1-r^{n+1}}{1-r} \] Note that the sum runs from k=0 to k=n and the it is \(r^{n+1}\) on the numerator of RHS.
I noticed that 0 which makes it 0 right?
???
k-0
Let me just use your formula instead of my teachers.. hang on.
No. \(\displaystyle \sum_{k=0}^nar^k\) means \(ar^0+ar^1+ar^2+\cdots\) all the way up to n.
I seriously dont see how you got that. Im still getting 4.
Yes the answer is 4. Now I am confused on how you got the answer.
BWHAHA thank you anyways!
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