Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction.____HNO3 + ____S ____NO + ____H2SO4
@jhonyy9
how you begine the ballance ? on the left side there is one H on the right side there are 2 H
Thats what confuses me. The whole process
N is equale O there are 3 on left and 5 on right S is equale do you understand it ?
Not all the way....
what is the common multiplie for 3 and 5 in case of oxigen ?
Man I dont even know
but i think than we begin with hydrogen will be more usefully check please there than you multiplie the left side by 2 so will be 2HNO3 because on the right side there are 2 hydrogen yes ? so than will be on the left side 2*3 = 6 oxigen - yes ?
Yes!
on the lrft side multiplie the NO by 2 so will get 2NO this mean that will result on the right side 2O + 4O = 6 oxygen so the sides by oxygen will be in equilibru yes ?
Yes :)
and how you think we have got the equilibru completly for every two side ?
Yeah
sure ?
I think so hah
ok. so was hard ?
Yeh pretty much lol thanks for the help though!
was my pleasure good luck bye bye
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