Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction.____HNO3 + ____S ____NO + ____H2SO4
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (liaannne):
@jhonyy9
jhonyy9 (jhonyy9):
how you begine the ballance ?
on the left side there is one H on the right side there are 2 H
OpenStudy (liaannne):
Thats what confuses me. The whole process
jhonyy9 (jhonyy9):
N is equale
O there are 3 on left and 5 on right
S is equale
do you understand it ?
OpenStudy (liaannne):
Not all the way....
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jhonyy9 (jhonyy9):
what is the common multiplie for 3 and 5 in case of oxigen ?
OpenStudy (liaannne):
Man I dont even know
jhonyy9 (jhonyy9):
but i think than we begin with hydrogen will be more usefully
check please there than you multiplie the left side by 2 so will be 2HNO3 because on the right side there are 2 hydrogen
yes ?
so than will be on the left side 2*3 = 6 oxigen - yes ?
OpenStudy (liaannne):
Yes!
jhonyy9 (jhonyy9):
on the lrft side multiplie the NO by 2 so will get 2NO this mean that will result on the right side 2O + 4O = 6 oxygen so the sides by oxygen will be in equilibru
yes ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (liaannne):
Yes :)
jhonyy9 (jhonyy9):
and how you think we have got the equilibru completly for every two side ?
OpenStudy (liaannne):
Yeah
jhonyy9 (jhonyy9):
sure ?
OpenStudy (liaannne):
I think so hah
Still Need Help?
Join the QuestionCove community and study together with friends!