Question

What is the standard form of the equation of the circle with center (-2, -3) and a radius of SQR OF 2/4?

Answer 1

@asnaseer

Answer 2

we just did the standard equation of a circle - remember a circle centered at (a,b) with radius r has equation:\[(x-a)^2+(y-b)^2=r^2\]

Answer 3

\[(X+3)^2+(Y+2)^2=1/8\]

Answer 4

VERY close - remember they said the radius is \(\sqrt{\frac{2}{4}}=\sqrt{\frac{1}{2}}\)

Answer 5

:(, WHAT DID I DO WRONG? I DONT UNDERSTAND

Answer 6

I didn't mean to do all caps

Answer 7

lol - don't worry :)

Answer 8

you are given\[r=\sqrt{\frac{2}{4}}=\sqrt{\frac{1}{2}}\]therefore \(r^2=?\)

Answer 9

hey @flowey15

Answer 10

you also have the X/Y swapped

Answer 11

ohh,

Answer 12

omg im sorry, we have been righting the radius wrong

Answer 13

ohhh - ok, so radius \(r=\frac{\sqrt{2}}{4}\) which means \(r^2=\frac{2}{16}=\frac{1}{8}\)

so you got that part correct :)

you just need to fix the X/Y parts

Answer 14

\[(x+2)^2+(y+3)^2=1/8\]

Answer 15

bingo! well done! :)

Answer 16

YAYY, THANKS SOOOO MUCH, YOUR THE BEST!!!!

Answer 17

you are more than welcome my friend - maths is mostly about practice - the more you practice the better you'll get :)