Question

2. A 2.0 kg block rests on a level surface. The coefficient of static friction is µs = 0.60, and the coefficient of kinetic friction is µk = 0.40. A horizontal force, F, is applied to the block. As F is increased, the block begins moving. Describe how the force of friction varies as F increases from the moment the block is at rest to when it begins moving. Indicate how you could determine the force of friction at each value of F―before the block starts moving, at the point it starts moving, and after it is moving.

Answer 1

I don't think I can help with this one i'm sorry :'(

Answer 2

its ok ..... thanks for trying though

Answer 3

:'( this is the first science question i have ever seen that i don't have an answer to

Answer 4

its fine you at least tryed

Answer 5

okay well there is a medal for you

Answer 6

and there's one for you.... thanks

Answer 7

thanks :) lol

Answer 8

your welcome

Answer 9

still no one answered you? wow

Answer 10

nope

Answer 11

(._.) *sigh* give me a min i'll try my best

Answer 12

Well, since it is a force question, you're best helper will be Newton's second law.
ΣF=mΣa
Now, you'll have to analyse the situations.
First the block does not move even if a force is exerted.
As the force increases until one point, the static friction force suddenly gives way and turns into kinetic friction because the block is moving.
So first case is ΣF=F−Ffs=0
so,F=Ffs
Second case is ,ΣF=F−Ffk=ma

Answer 13

that help any?

Answer 14

yes thank you

Answer 15

no problem :)

Answer 16

hi milan

Answer 17

Hi

Answer 18

milan do you know anything about this?

Answer 19

No sorry

Answer 20

okay :)

Answer 21

need more info ayonnaleflore?

Answer 22

no my teacher is about to help me but thanks for everything

Answer 23

oh okay :) cool