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Mathematics 17 Online
MsBrains (ms-brains):

Can someone please help? http://prntscr.com/afofwh

MsBrains (ms-brains):

@FortyTheRapper

OpenStudy (fortytherapper):

Radical is pretty much square root in human terms Let's begin by finding C using the Pythagorean theorem. Are you familiar with that?

MsBrains (ms-brains):

Sorta, I'm learning it in class this week.

OpenStudy (fortytherapper):

So, basically it's \[a^2+b^2=c^2\] We take our value of a and square it, we take our value of b and square it, then we add them up and put a square root symbol over that answer

MsBrains (ms-brains):

Alright so, 5=2.2360679775 We still add them up even if they are the same number?

OpenStudy (fortytherapper):

Oh, you took the square root of the number 5, but we want to square the number 5 (Multiply it by itself)

OpenStudy (fortytherapper):

Then you put the sqrt over it \[\sqrt(a^2+b^2)\]

MsBrains (ms-brains):

So like 2.2360679775 * 2.2360679775 = 5?

OpenStudy (fortytherapper):

We would do for A, let's say \[5^2\]

OpenStudy (fortytherapper):

B is the same number in this case, so we do the same for B

MsBrains (ms-brains):

sqrt(5^2 +5^2) so we just this equation?

OpenStudy (fortytherapper):

Right, so what does 5^2 equal?

MsBrains (ms-brains):

25

OpenStudy (fortytherapper):

Right, so now we do sqrt(25+25). 25 + 25 = 50 right, so would you agree that \[C^2 = \sqrt(50)\]

MsBrains (ms-brains):

Yes, So that's what I write for C?

OpenStudy (fortytherapper):

For this question, yes \[\sqrt{50} \] is in simplified radical form

OpenStudy (fortytherapper):

I mean unsimplified

MsBrains (ms-brains):

Alright awesome, now to part b?

OpenStudy (fortytherapper):

Yep To simplify this, we need to know our perfect squares like 1,4,9, etc 1 = 1*1 4 = 2*2 9 = 3*3 and so on

MsBrains (ms-brains):

Okay, so we're going to simplify \[\sqrt{50}\]

MsBrains (ms-brains):

right?

OpenStudy (fortytherapper):

Correct

OpenStudy (fortytherapper):

In order to simplify it, we have to find 2 numbers that multiply to 50 One of those numbers, though, has to be a perfect square

MsBrains (ms-brains):

\[\sqrt{2*5*5}\]

MsBrains (ms-brains):

Like that ^

OpenStudy (fortytherapper):

Yes! Right numbers, we just need to separate them \[\sqrt{2}\sqrt{5*5}\] 5*5 = 25, so \[\sqrt{2}{\sqrt{25}}\]

OpenStudy (fortytherapper):

See how that bottom one equals \[\sqrt{50}\]

MsBrains (ms-brains):

\[\sqrt[5]{2}\]

OpenStudy (fortytherapper):

Yes, \[5\sqrt{2}\] is in simplified form, good job

OpenStudy (fortytherapper):

Just remember to make it a big 5 and not a little 5

MsBrains (ms-brains):

So thats what goes for part B?

OpenStudy (fortytherapper):

Yep, \[5\sqrt{2}\], you found part B

MsBrains (ms-brains):

How do we find it to the nearest hundredth now?

OpenStudy (fortytherapper):

I like part C because C stands for calculator lol Let's put \[\sqrt{50}\] in the calculator and see what we get

MsBrains (ms-brains):

this is what i got http://prntscr.com/afoze2

OpenStudy (fortytherapper):

It gave 7.07, which is in the hundredths, sounds good for a Part C answer!

MsBrains (ms-brains):

Awesome! Thank you so much! Do you think you can help with 1 more problem?

OpenStudy (fortytherapper):

Yeah, let's see it

MsBrains (ms-brains):

Alright, lemme open a new thread. :)

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