Question

A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.




a. Find BC, the distance from Tower 2 to the plane, to the nearest foot.
b. Find CD, the height of the plane from the ground, to the nearest foot.

Answer 1

I know the answers but I want someone to explain the steps that were taken to solve it.

Answer 2

Nice problem. It will involve the Pythagorean theorem.

Answer 3

Maybe.

Answer 4

The formula for that would be a2 + b2 = c2 right?

Answer 5

yes

Answer 6

so 16^2 + 24^2 = c^2

Answer 7

832

Answer 8

no never mind that isn't right

Answer 9

no those are degrees we need to work sin x = Height / hypotenus into this

Answer 10

I am working on some equations so my response time will be slow.

Answer 11

The height (CD) is Sin 24 = Height/ Hypotenus2 which equal sin 14 Height / Hypotenus1

Answer 12

I am trying the figure out how the distance between the towers works into this.

Answer 13

but we don't know what the height is

Answer 14

sorry I'm confused

Answer 15

I had a typo above the angle is 16 not 14.

Yes there are a lot of unknowns here but we need some related equations.

I'm confused right now also, but hang with me while I try to think it out.

Answer 16

Okay thanks for helping

Answer 17

This will help

a1 - a2 = 7600 and both triangles have the same height. Those are related.

Answer 18

would it be sin(16)=x/7600?

Answer 19

No that's not going to work. What is x?

Answer 20

BC

Answer 21

because thats what we are trying to find.