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Mathematics 16 Online
MsBrains (ms-brains):

http://prntscr.com/afr3bw

MsBrains (ms-brains):

@kayders1997

563blackghost (563blackghost):

Use Pythagorean Theorem.... \(\Huge{a^{2}+b^{2}=c^{2}}\)

OpenStudy (sweetburger):

|dw:1458080989842:dw|

OpenStudy (kayders1997):

Do you understand? @Ms-Brains

MsBrains (ms-brains):

Gimme 1 sec to solve this

563blackghost (563blackghost):

So like from @sweetburger post we would input the sides of the triangle... \(\Huge{23^{2}+b^{2}=32^{2}}\) In which we simplify... \(\Huge\color{purple}{529 + b^{2}=1024}\) In which you would subtract c by a to get b.... \(\Huge\color{green}{1024-529=b^{2}}\) The answer you get you would then find the square root.... \(\Huge\color{red}{\sqrt {1024-529}=b}\)

MsBrains (ms-brains):

\[\sqrt[10]{5}\]

MsBrains (ms-brains):

I'm so confused still...

OpenStudy (kayders1997):

What you confused about?

MsBrains (ms-brains):

What the answer is..?

OpenStudy (kayders1997):

First what is the difference between 1024-529

OpenStudy (kayders1997):

Actually do you want to start over or do you understand where they are getting the numbers from to plug into the equation?

MsBrains (ms-brains):

I got no clue.. Can we start over please?

OpenStudy (kayders1997):

Yes

OpenStudy (kayders1997):

Say we have a triangle we have side a b and c, c will be the longest, a and b will be the legs of the triangle so it doesn't matter what one you call a and b, but c will always be the longest or the hypotenuse does this make sense?

OpenStudy (kayders1997):

When I say legs of the triangle I'm saying the sides that meet at a right angle

OpenStudy (kayders1997):

You okay?

MsBrains (ms-brains):

Hey, yeah sorry my OS froze

OpenStudy (kayders1997):

That's okay

OpenStudy (kayders1997):

Because we have 2 sides we can you the pythgrean theorem which says if your tying to find 1 side and you have 2 known side you can use the formula A^2+B^2=C^2 does this make sense?

MsBrains (ms-brains):

Wait, I think I got, the final answer would be 22.2 ft, right?

OpenStudy (kayders1997):

Yes

MsBrains (ms-brains):

Thank you!

OpenStudy (kayders1997):

You're welcome :)

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