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OpenStudy (anonymous):
OpenStudy (anonymous):
@563blackghost another?:) ill medal again
563blackghost (563blackghost):
one sec...standard deviation was always tricky for me...
OpenStudy (anonymous):
same, :(
OpenStudy (miastarr):
@mathmale
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563blackghost (563blackghost):
First we would find the mean of the set of numbers so....
\(\Huge{\frac{14+34+23+50+25+16+48}{7}=\color{red}3\color{red}0}\)
We would then subtract the mean with each number and square that number....
\(\Large\frac{(14-30)^{2}+(34-30)^{2}+(23-30)^{2}+(50-30)^{2}+(25-30)^{2}+(16-30)^{2}+(48-30)^{2}}{7}\)
In which this would simplify toooo....\(\LARGE\color{red}{180.85714...}\) We would then find the sqaure root of this number which would be...
\(\Huge\color{red}{13.44...}\)
OpenStudy (anonymous):
so B?
OpenStudy (anonymous):
i would have never gotten that wow
OpenStudy (anonymous):
these are hard haha
563blackghost (563blackghost):
But a website says its 14.5 so my outcome is incorrect...but i dont know how...
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