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Mathematics 10 Online
OpenStudy (anonymous):

WILLL FAN AND MEDAL HELP PLZ!

OpenStudy (anonymous):

OpenStudy (anonymous):

@563blackghost another?:) ill medal again

563blackghost (563blackghost):

one sec...standard deviation was always tricky for me...

OpenStudy (anonymous):

same, :(

OpenStudy (miastarr):

@mathmale

563blackghost (563blackghost):

First we would find the mean of the set of numbers so.... \(\Huge{\frac{14+34+23+50+25+16+48}{7}=\color{red}3\color{red}0}\) We would then subtract the mean with each number and square that number.... \(\Large\frac{(14-30)^{2}+(34-30)^{2}+(23-30)^{2}+(50-30)^{2}+(25-30)^{2}+(16-30)^{2}+(48-30)^{2}}{7}\) In which this would simplify toooo....\(\LARGE\color{red}{180.85714...}\) We would then find the sqaure root of this number which would be... \(\Huge\color{red}{13.44...}\)

OpenStudy (anonymous):

so B?

OpenStudy (anonymous):

i would have never gotten that wow

OpenStudy (anonymous):

these are hard haha

563blackghost (563blackghost):

But a website says its 14.5 so my outcome is incorrect...but i dont know how...

OpenStudy (anonymous):

which website did you use?

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