Question

What is the best way to solve the following equations:
a. 5x^2+12x-3=0
b. x^2-4x=8
c. 4x^2-25=0
d. x^2-5x+6=0
solve by: quadratic formula, completing the square, square root method, factoring

Answer 1

I think they are...
a. quadratic formula
b. square root method
c. factoring
d. completing the square
Are these correct?

Answer 2

d. x^2-5x+6=0 factors (x -3)*(x - 2)

Answer 3

c. 4x^2-25=0 will factor but taking square roots may be easier.

4x^2 = 25

2x = +5 or 2x = -5

and so on

Answer 4

x^2-4x=8 Maybe complete the square

5x^2+12x-3=0 Maybe the Quadratic Formula

I'm not saying that any of my thoughts are correct.

I would factor those which will factor and QF the rest.

But, that is not the question.

Answer 5

@fairygirl0404 What happened to our other helpers. We need more input.

Answer 6

@agent0smith

Answer 7

@Directrix I agree with you about factoring and QF the rest...you are right it is asking to break them up more. Thanks for you input. Greatly apperciated. :)

Answer 8

You are welcome.

Answer 9

@Directrix because I voted yur response Best, does that mean no one will see my problem now? Or is still open till I close it?

Answer 10

Here's my list:

1. Quadratic Formula
2. Completing the Square
3.Square Roots
4. Factoring.

Answer 11

a. 5x^2+12x-3=0 - QF
b. x^2-4x=8 - QF or complete the square
c. 4x^2-25=0 - factor
d. x^2-5x+6=0 - factor

Answer 12

If you close the problem helpers can still work on it. And, there can be more than one Best Response." Closing means the question goes over into another folder on OS but we can still see it.

Answer 13

@Directrix LOL I'll let you know the outcome when I get my paper back. Thanks again for all your help.

Answer 14

Check out @agent0smith 's post.

Answer 15

Alrighty, then, @fairygirl0404 close if you are ready.

Answer 16

I did but there can't be two factors. It is a = 1 and so on.

Answer 17

...What?