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Geometry 14 Online
OpenStudy (sbuck98):

Someone check my answer and help me round it.

OpenStudy (sbuck98):

14.47

OpenStudy (sbuck98):

Actually, 14.477

OpenStudy (dinamix):

its 75,5 @ sbuck98

OpenStudy (anonymous):

arc sin 2/8

OpenStudy (dinamix):

arc cos not sin

OpenStudy (dinamix):

arc cos 1/4

OpenStudy (sbuck98):

Could you help me with a few more until I get this

OpenStudy (anonymous):

oh yes

OpenStudy (sbuck98):

How would I write 75.5 in pie?

OpenStudy (anonymous):

pie is 22/7 right

OpenStudy (anonymous):

75.5 x 22/7

OpenStudy (sbuck98):

yes

OpenStudy (sbuck98):

Thank you

OpenStudy (anonymous):

237.285714286

OpenStudy (anonymous):

that's your answer

OpenStudy (sbuck98):

It showed that was incorrect for my practice too:( I'll never get the hang of this:(((((

OpenStudy (sbuck98):

@Daniel56k

OpenStudy (anonymous):

okay so can i see the question

OpenStudy (sbuck98):

I got it, I solved it wrong, it was 75.52. could you help with more please

OpenStudy (sbuck98):

@Daniel56k

OpenStudy (anonymous):

do u know this SOH CAH TOA

OpenStudy (sbuck98):

Not much, help me on this one if you'd rather @Daniel56k

OpenStudy (anonymous):

arc tan 3/9

OpenStudy (anonymous):

18.435

OpenStudy (sbuck98):

is that angle A? & then I just divide by cosine and 2/8? @Daniel56k

OpenStudy (sbuck98):

Please hurry & help me, I'm using tacobells wifi bc my home got flooded in the bad weather. @Daniel56k

OpenStudy (mathmale):

@sbuck98: would you please share all of your work, so that the rest of us will know how you got your results? You may get better feedback that way.

OpenStudy (sbuck98):

I've been asking someone to step me through this. Can you? I do online school so I've had no lessons on this due to my lack of internet. @mathmale

OpenStudy (sbuck98):

I just need someone to teach me how to find the angle. I know how to do the last part. Could you explain? @mathmale

OpenStudy (mathmale):

Note that this triangle is a right triangle, because one of the angles is 90 degrees. Because of this fact, you can use the Pythagorean Theorem to find the length of the hypotenuse. Does this vocabulary sound familiar to you?

OpenStudy (mathmale):

Your right triangle has two legs (as well as the hypotenuse). Square the lengths of these two legs. Sum up those 2 squares. Find the sqrt of the result. Mind sharing your work?

OpenStudy (sbuck98):

The pythagroean theorem is that they're all equal right?

OpenStudy (sbuck98):

Okay, I got 12 for my sum. and the square root of 12 as 2 sqrt 3

OpenStudy (mathmale):

Sorry, no. Better look up Pythagorean Theorem; it's one of the most basic tools in algebra and geometry, also in trig. Write out the P. Theorem after you've looked it up.

OpenStudy (mathmale):

But did you square the lengths of the legs? I think not. Must do that.

OpenStudy (sbuck98):

The square of the hypotenuse is equal to the sum of the squares of the other two sides.

OpenStudy (sbuck98):

How do I square the other two legs when I don't know what they are?

OpenStudy (mathmale):

Share your png file. Looks like we're talking about 2 different problems here. Best if you'd please share only one problem per post to avoid this confusion.

OpenStudy (sbuck98):

OpenStudy (mathmale):

Explain what you mean by "but I don't know the lengths of the legs." ??

OpenStudy (mathmale):

Review: a right triangle has ONE hypotenuse and TWO legs.

OpenStudy (sbuck98):

9+3=12, you told me to square the sum.. then the other two legs that I don't know.

OpenStudy (mathmale):

What does "sum" mean to you? We have a major misunderstanding here, I'm afraid.

OpenStudy (sbuck98):

The sum is the total amount.....

OpenStudy (mathmale):

And what does "square" mean in this context?

OpenStudy (sbuck98):

Square root... A perfect square, the square root of 12 is 2 sqrt 3

OpenStudy (mathmale):

True, but I asked y ou to square the lengths of the 2 legs, not to find their square roots.

OpenStudy (mathmale):

What are the lengths of the 2 legs?

OpenStudy (sbuck98):

9, and 3.

OpenStudy (mathmale):

What is the square of 9? No, not the square root, but the square.

OpenStudy (sbuck98):

3? isn't squaring & square root the same thing?

OpenStudy (mathmale):

Absolutely not. The square root of 4 is 2. The square of 4 is 16, which is 4 times 4.

OpenStudy (sbuck98):

oh so it's 81 & 9!

OpenStudy (sbuck98):

81+9=90

OpenStudy (mathmale):

Yes. Now add those two squares together (that is, find their sum).

OpenStudy (sbuck98):

I did above

OpenStudy (mathmale):

Now you'll need to find the length of the hypotenuse. How would you do that? Important: what is the name of the operator you must apply to 90?

OpenStudy (sbuck98):

Pythagorean theorem?

OpenStudy (mathmale):

You squared 9 to get 81. You squared 3 to get 9. You added these two squares together. Now, you want to find the length of the hypotenuse. What is the opposite of "square"?

OpenStudy (sbuck98):

sqrt

OpenStudy (mathmale):

Yes. What is sqrt(90)?

OpenStudy (sbuck98):

3 sqrt 10

OpenStudy (mathmale):

Yes. That's the length of the hyp. Find the value of Sqrt(10) using your calculator.

OpenStudy (sbuck98):

3.16

OpenStudy (mathmale):

Now multiply tht by 3.

OpenStudy (sbuck98):

9.48

OpenStudy (mathmale):

Now, how many decimal place accuracy do you want?

OpenStudy (sbuck98):

3

OpenStudy (sbuck98):

or 4

OpenStudy (sbuck98):

4 would be best.

OpenStudy (mathmale):

type into your calculator: Sqrt(90). Round off the decimal fraction to 4 places. Your result?

OpenStudy (sbuck98):

9.486

OpenStudy (mathmale):

That's 3 decimal place accuracy. Thought you wanted 4 decimal places.

OpenStudy (sbuck98):

That's fine

OpenStudy (mathmale):

Satisfied? Learn something helpful?

OpenStudy (sbuck98):

Yes

OpenStudy (mathmale):

Good to work with you. Good luck!

OpenStudy (sbuck98):

Wait, I still have to find the angle... @mathmale

OpenStudy (mathmale):

Can you find the length of the "adjacent side" of the u nknown angle? What is it?

OpenStudy (sbuck98):

no

OpenStudy (mathmale):

An "adjacent side" is the side right next to the angle you're trying to measure. Look at your diagram again.

OpenStudy (mathmale):

In other words: Find Angle A. What's the length of the side (Not the hypotenuse) next to Angle A?

OpenStudy (mathmale):

and what's the length of the side OPPOSITE Angle A?

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