Question

http://oi68.tinypic.com/5a56yd.jpg

Answer 1

@Photon336

Answer 2

@Cuanchi
@aaronq

Answer 3

for for starters spontaneuos in the forward direction would imply delta G<0

Answer 4

@Photon336 Right so how exactly do I set this one up? I've been trying to no success : (.

Answer 5

damn I g2g but i'll tag someone else @sweetburger

Answer 6

thanks

Answer 7

Goodness this requires a hell of a lot of steps. I am thinking we start by using the expression \[\Delta G = -RT \ln(Q_p)\]

Answer 8

\[Q_p = K_p\]

Answer 9

Given we know T the Delta G and R(gas constant) we can solve for K_p

Answer 10

Alright. Sorry I had to step away.

Answer 11

@sweetburger Are you able to go through the steps? I'm really lost on this one.

Answer 12

2600 J/mol = -8.314 x 298 x ln K
K= e^-1.049 = 0.35
0.35= (4.75)^2/(9.5 x "I2") ==> I2 = (4.75)^2/(9.5 x 0.35)= 6.79 atm

Answer 13

That looked easier than I thought. Thanks!