Question

Determine the oxidizing and reducing agents after answering the following questions. First, determine the oxidation number of every atom on both sides of the arrow.

KMnO4 + H2S + HCl KCl + MnCl2 + H2O + S8
1. Did Cl change oxidation number?
2. Did Oxygen change oxidation number?
3. Did H change oxidation number?
4. Did Mn change oxidation number?
5. Did S change oxidation number?
6. What is the oxidizing agent?
7. What is the reducing agent?

Answer 1

@Photon336
@Cuanchi

Answer 2

@sweetburger

Answer 3

This takes some practice because there are rules to oxidation

Answer 4

so naturally the sum of oxidation states adds up to zero

Answer 5

ok

Answer 6

starting with number one would the answer be no?

Answer 7

........

Answer 8

@Kittykatiehunt

Answer 9

the arrow is suppose to be between HCl and KCl

Answer 10

are you still here @Photon336

Answer 11

Redox reaction....

KMnO4(aq) + H2S(aq) + HCl(aq) --> KCl(aq) + MnCl2(aq) + H2O(l) + S8(s) ...... unbalanced

Get rid of spectator ions.... Show oxidation states....
+7-2........ +1-2...+1 ...... +2 ........+1-2 ....0
MnO4^- + H2S + H+ --> Mn2+ + H2O + S8

1. Did Cl change oxidation number? == no, it is a spectator ion
2. Did Oxygen change oxidation number? == no
3. Did H change oxidation number? == no
4. Did Mn change oxidation number? == yes, from +7 to +2, it is reduced
5. Did S change oxidation number? == yes, from -2 to 0, it is oxidized
6. oxidizing agent = MnO4^- ion
7. reducing agent = H2S

MnO4^- + H2S + H+ --> Mn2+ + H2O + S8
16(MnO4^- + 8H+ + 5e- --> Mn2+ + 4H2O) .... reduction half-reaction
5(8H2S --> S8 + 16H+ + 16e-) ............ ........... oxidation half-reaction
---------------- ----------------- --------------- -----------------
16MnO4^- + 128H+ + 40H2S --> 16Mn2+ + 5S8 + 80H+ + 64H2O
simplify
16MnO4^- + 48H+ + 40H2S --> 16Mn2+ + 5S8 + 64H2O ..... balanced net ionic equation

Answer 12

That's everything :)

Answer 13

you are awesome!!!

Answer 14

Thanks

Answer 15

Let's go to H2S

We know that H's oxidation state is 1 and we have two atoms so that's 1x2 = 2

For sulfur it's going to be -2

Answer 16

ok