A ball is dropped from 74 feet and bounces to 5/8 of its height each time. How far will it travel by the time it comes to rest?
It's a geometric series. Maybe you have some idea of how to find the sum of one.
@agent0smith a1 (1-r^n)/(1/r) 74 (1-5/8^n)/(1/r)
Do you know how to find n though?
wait..... OHHHHHHHHHHHHHHH
lol I get it, is this an infinite geometric series?
74/ 1-5/8???
@agent0smith
You might want to draw it out. You're on the right track though... but a ball bounces up and then falls back down
so the answer is 197.33 feet right?
is that correct?
@agent0smith
Draw it out, like a bouncing ball, and you might see what you're missing.
please, I don't have a lot of time and I don't want to spend a lot of time on ONE question
May you please just tell me if this answer is correct or not
if not please just give me the EQUATION
Well, I'm about to go to bed, and your answer is wrong. There isn't a particular equation.
please try to explain it the shortest way possible (because when you started talking about drawing a ball or something, bro I know there's a shorter way)
Because that's how you figure it out for yourself - drawing out the path.
Sorry I know i'm being rude since i'm asking for help but as you can see this is a close question so i'm not that desperate so PLEASE give me a shortcut or no thanks I don't need a lecutre
all right well no that's I don't need a lecture, sorry i'm really busy
Don't use 74 as the first term. Add that at the very end. The first term of the infinite series should be the first bounce height. Find the infinite sum for that. Then... keep in mind it bounces up AND down.
I have no idea but whatever, i'll figure this out later
https://www.youtube.com/watch?v=tqTJZEglrvc Look at how he does this. All I did was google "how to find the distance travelled by a bouncing ball"
btw, there isn't a shortcut for these. This is how I solved these kind of problems the first time I did them.
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