Question

Weak acids:
Select one:
a. are always more soluble than strong acids
b. have a higher degree of dissociation than do strong acids
c. only ionize a fraction of their molecules
d. always produce weak conjugate bases

Answer 1

Strong Acids (examples HCl, HI, HBr.) fully dissociate and completely ionize.

Weak Acids (examples CH3COOH) only partially dissociate and release only a small fraction of the total possible ions that could be release.

Answer 2

Thank you so much! Do you have time for one more easy question??

Answer 3

sure

Answer 4

Go ahead and ask away.

Answer 5

Okay so the next one is:

Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction.____FeCl3 + ____H2S ____FeCl2 + ____S + ____HCl

I already balanced it so its 2 FeCl3 + H2S --> 2FeCl2 + S + 2HCl
I just need help with the oxidation and reduction identification.

Answer 6

(Fe^3+) + e- (-->) Fe^2+ (shift of 1 electron)

H2S (-->) S + 2H^+ + 2e (shift of 2 electrons)

to equal the electron shifts we must multiply the top equation by a factor of 2
2((Fe^3+) + e- (-->) Fe^2+) = 2(Fe^3+) + 2e- (-->) 2Fe^2+

Now we combine that newly formed equation and the bottom equation

H2S + 2(Fe^3+) + 2e- (-->) S + 2H^+ + 2e- + 2Fe^2+

2e- appears on both sides of the chemical equation so they cancel out
you are left with
H2S + 2 Fe^3+ (-->) S + 2H^+ + 2Fe^2+

Answer 7

Im still just a little confused. I know that losing electrons means the element is oxidated and gaining electrons means the element is reduced. but thats kinda all i understand

Answer 8

Well the first step for writing redox reactions is separating the reactions into their respective oxidization and reduction reactions. In the steps I wrote above, the top reaction is the reduction reaction and the bottom reaction is the oxidization reaction. Now to balance this redox reaction we must not only have the same number of atoms on both side, but we must also have the same number of electrons exchanged in both directions. In the top reduction reaction 1 electron is on the reactant side. In the bottom oxidization reaction 2 electrons are on the product side. We must have an equal amount of electrons on both sides of the equation. SOOO we multiply the top reduction reaction by a factor of 2 to equal the electron transfer.
At this point you just have to combine both equations into one single large equation and cancel out what appears on both sides.

Answer 9

Oh okay i gotcha now lol

Answer 10

Quick question. Do you know if you are expected to balance this in a basic or acidic conditions, cus that may change the answer.

Answer 11

it doesnt say

Answer 12

Alright ignore that there should be no changes then :)

Answer 13

Thank you so much for your help!! :)

Answer 14

Np, glad to help out :D