Question

SOMEONE PLEASE HELP ME WITH THIS IM FAILING ALGEBRA WILL MEDAL

Describe what the rectangle represents and find the dimensions of the rectangle in
terms of x, assuming the area is represented by the polynomial
2
x x8 9 .
Using a specific value for x, find the dimensions (length x width) and area of the
rectangle.

Answer 1

Your post is not clear.
Can you show it better, or take a picture of the actual problem?

Answer 2

Describe what the rectangle represents and find the dimensions of the rectangle in
terms of x, assuming the area is represented by the polynomial
x^2+8x-9

Answer 3

@mathstudent55

Answer 4

You can try factoring the polynomial.

Answer 5

\(x^2 + 8x - 9 = (x + 9)(x -1)\)

Now use a value of x greater than 1.

Answer 6

Since the area of a rectangle is the length multiplied by the width, and the area is \(x^2 + 8x - 9\), and it factors into the product \((x + 9)(x - 1)\), you can say that x + 9 is the length of the rectangle, and x - 1 is the width of the rectangle.

Now come up with any number greater than 1 for x, such as 2, 3, 4, 10, etc.
If you use that number for x in x + 9, what do you get? This is the length.
If you use that number for x in x - 1, what do you get? This is the width.
Then multiply the length and width together to find the area of the rectangle.
Then use the same value of x in \(x^2 + 8x - 9\) and verify that you get the same area.

Answer 7

Okay, thanks

Answer 8

You're welcome.