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evaluate the square root of 24-x when x=6. Write the answer in simplified radical form.
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idk what radical form is
can you draw that or something
OK so √24 is 2√3
2√3-6
? i got -5.33333333 idk if that correct but lemme try again
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U have to rationalize the √24
√24=√2*√12 √12=√6 √3 √6=√2√3
I have a pair of 2 and 3
\[\sqrt{24 - x}\] \[\sqrt{24 - 6}\]
\[\sqrt{18}\]
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oh now i get it
@usernamenotfound you are neglecting the -6
So it's gonna be √18=√9√2 √9=√3√3
6√2
Close \[3\sqrt{2}\]
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