Question

Can someone check my answer?

Answer 1

What is the question and answer? :)

Answer 2

Find the product of (x + (3+5i))^2.
=x^2 + 2(x)(3+5i)+(3+5i)^2
=x^2 + 2(3x+5xi)+(3+5i)2
=x^2 + 6x + 10xi + (3+5i)^2
(3+5i)^2= 3^2 + 2(3*5i) +(5i)^2
=9+6+5i+25i^2
=9+11i-25
(x + (3+5i))2 = x^2 + 6x+10xi+9+11i-25

Answer 3

@kayders1997

Answer 4

Just a second

Answer 5

I agree with you until the last two terms plus is this imaginary number stuff, because i² can be changed to -1

Answer 6

Oh yeah I see you did change it okay good

Answer 7

Yes, i was doing good with this stuff until they threw in complex number.

Answer 8

So its just the 5th term that I got different, and plus you can add your constants together because there are a couple

Answer 9

Okay I think I know what you did wrong

Answer 10

Your third step was good until here x²+6x+10xi+(3+5i)²
So than you would have to do x²+6x+10xi+(3+5i)(3+5i) So it is expanded out properly I think you might have just made a little error there

Answer 11

You need to multiply them not add them

Answer 12

So do you want to try that expansion part again? :)

Answer 13

Yeah Ill try it, kinda think I understand. One second.

Answer 14

If you want to take a look at my work I can show you the steps I did

Answer 15

If I can figure out how to take a picture on this computer XD

Answer 16

would it be 9+55i?

Answer 17

Fine Ill type it all out
(x+(3=5i))²
(x+(3+5i))(x+(3+5i)) distribute
x²+x(3+5i)+x(3+5i)+(3+5i)² distribute and expand
x²+3x+5xi+3x+5xi+(3+5i)(3+5i) add like terms
x²+6x+10xi(3+5i)(3+5i) this is where we are ate it is 9 but not 55i

Answer 18

So just look at (3+5i)(3+5i) We are going to have to foil this out first outsides insides last