Question

i needed to edit this

Answer 1

What foci?
What eclipse?

Answer 2

Check this out. It might help. http://www.mathopenref.com/ellipsefoci.html

Answer 3

of the Eclipse? man that's going to be ecliptical =)

Answer 4

\(\bf 4x^2+49y^2=196\implies \cfrac{\cancel{4}x^2}{\cancel{196}}+\cfrac{\cancel{49}y^2}{\cancel{196}}=1\implies ?\)

Answer 5

Not to make fun, of course, but you mean "ellipse," not "eclipse."

Answer 6

Do you know what foci are, and where they're located on graphs of elllipses?

The following web page may be useful to you:

https://www.google.com/search?q=ellips&tbm=isch&imgil=Ffmol-mQlBnB5M%253A%253BP2fc0JwzVJcqEM%253Bhttp%25253A%25252F%25252Fwiki.eanswers.com%25252Faf%25252FEllips&source=iu&pf=m&fir=Ffmol-mQlBnB5M%253A%252CP2fc0JwzVJcqEM%252C_&usg=__AfdwAv0J5pKgtMwDor9mxCDFTAs%3D&biw=1360&bih=669&ved=0ahUKEwjC4dKiucbLAhWEtYMKHSo1Bk8QyjcIJg&ei=_vfpVsLqFITrjgSq6pj4BA#imgrc=Ffmol-mQlBnB5M%3A

Three letters, a, b and c, are used to describe the ellipse. Note that the illustration shows that the focus is distance c from the origin (center of the ellipse).

This illustration shows a horizontal ellipse. Note that a^2 will go underneath x^2 in the equation for an ellipse \[\frac{ x^2 }{ a^2 }+\frac{ y^2 }{b^2 }=1.\]

Answer 7

\[\frac{ x^2 }{ 49 }+\frac{ y^2 }{ 4 }=1\]
\[\frac{ x^2 }{ 7^2 }+\frac{ y^2 }{ 2^2 }=1\]

Answer 8

Have you graphed ellipses before? If so, please graph the one you've posted here. Can you obtain a and b from the equation? (See surjithayer's work, above). If you have a and b, then you can find c. Again, c would be the distance from the origin to the right hand focus of this ellipse.

Answer 9

no i've never graphed ellipses before :/

Answer 10

compare with
\[\frac{ x^2 }{ a^2 }+\frac{ y^2 }{ b^2 }=1\]
a=7,b=2
\[b^2=a^2(1-e^2)\]
\[4=49(1-e^2)\]
\[1-e^2=\frac{ 4 }{ 49 },e^2=1-\frac{ 4 }{ 49 }=\frac{ 45 }{ 49 },e=\frac{ 3\sqrt{5} }{ 7 }\]
\[ae=7*\frac{\pm 3\sqrt{5} }{ 7 }=\pm3\sqrt{5}\]
foci are \[(\pm ae,0)~or~(\pm 3\sqrt{5},0)\]