Prove that a function g has a limit and find it. (full question and answer will be attached)
@Kainui here it is
Which function? It already gives the steps for solving in an intuitive way. Do you want the delta-epsilon proof?
I was reading and following the example. done this two styles. one with just evaluate the limit on scratch paper which I got 1/2 and the other way which requires the conjugate and usage of theorem 2.4. I also ended with up 1/2. WHy the heck does another book say -1? That doesn't make sense. The function is the g(x) that is the first snippet @ChillOut
first style as in calculus i... no words required. seemed faster but I know I gotta write. xD
Can you show me where it shows it is -1?
yeah sure hold on. I'll attach another screenshot
sorry my typing is messed up. it's 1 (looking at it again) , but still I don't see how that happens
weird... since x times x is x^2 -_-
plus when I was reading the example, it didn't do that >:/ and I was following the example before doing that problem
even Mr. Wolfy from Wolfram Alpha Inc says that the limit is 1/2
You are doing \(g(x)^2\), whereas in the example he multiplies by the conjugate.
Woops!
I didn't check the signal... All right. But you cannot modify the function... You should multiply by the conjugate both in the denominator and in the numerator
I did that -_- see my attempt on #18 I did use the conjugate
the 11111111111 file is from a study guide which is sometimes notorious for errors.
I have done this... calc 1 style... THIS and then check with Mr.Wolfy all of them is 1/2 how they got 1 is b******t
You should multiply by \(\large \frac{\sqrt{x+1}+1}{\sqrt{x+1}+1}\)
I did that already. first image where it says section 2.3 is my attempt which is modeled off the example.
what was done in the book is the correct way. what I found in a study guide was ridiculous because the denominator is already messed up.
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