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log(21x^3)−log(7x^2)=3 how to solve for x?
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first you'll use the log rule log(A) - log(B) = log(A/B)
using that rule turns `log(21x^3)−log(7x^2)` into what?
log(21^3/7x^2)=3
21/7=3 log10(3x)=3
good by default, logs are in base 10. So you don't need to state the base if it's base 10
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log(3x) = 3
10^3/3=3x/3 cancels out
answer is x=10^3/3
yep or 1000/3
even though i just solved it myself lmao
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nice work
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