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Mathematics 14 Online
OpenStudy (anonymous):

Convert to trigonometric form: z=4square root of 3+4 i

OpenStudy (kittiwitti1):

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hoot007 Convert to trigonometric form: z=4square root of 3+4 i \(\color{#0cbb34}{\text{End of Quote}}\) This?\[z=4\sqrt{3+4i}\]

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Oh wait the square root is only over the 3

OpenStudy (kittiwitti1):

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hoot007 Oh wait the square root is only over the 3 \(\color{#0cbb34}{\text{End of Quote}}\) Oh okay. Then this?\[z=4\sqrt{3}+4i\]

OpenStudy (anonymous):

Yes

OpenStudy (kittiwitti1):

Hmm. Well, I'll give you a hint first. What special right triangle has root(3) as one of the sides? :)

OpenStudy (anonymous):

so would it be 8(cos30 + i sin30)

OpenStudy (kittiwitti1):

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hoot007 so would it be 8(cos30 + i sin30) \(\color{#0cbb34}{\text{End of Quote}}\) Yep ^_^ Dang you figured that out really fast o_e

OpenStudy (anonymous):

Thank you

OpenStudy (kittiwitti1):

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hoot007 Thank you \(\color{#0cbb34}{\text{End of Quote}}\) No problem! Happy OpenStudying ♣

OpenStudy (anonymous):

Convert to standard form: z = 20(cos135 + i sin135)

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