Question

im needing a bit of help every answer is appreciated need asap!


What is the general form of the equation of the given circle with center A?

Answer 1

x2 + y2 + 6x − 24y − 25 = 0



x2 + y2 − 6x + 24y + 128 = 0



x2 + y2 + 6x – 24y + 128 = 0



x2 + y2 + 6x − 24y + 148 = 0

Answer 2

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". This form of the equation is helpful, since you can easily find the center and the radius.

Answer 3

(x – h)2 + (y – k)2 = r2 is the correct formula to use, EXCEPT that the exponentiation must be expressed as

(x – h)^2 + (y – k)^2 = r^2

or
\[ (x – h)^2 + (y – k)^2 = r^2\]

Answer 4

why?

Answer 5

Let's wait for a response from "fluffynose," please.

Answer 6

Note that the center, A, is given, as is the radius. What are you to do with this info along the way to writing the general equation for this circle?

Answer 7

fluffynose: We need your input. Please respond. If you're not sure of what to say, ask a pertinent question.

Answer 8

Given the center A(-3,12), and the radius, r=5, write the general form of the equation of this circle.

Use \[(x – h)^2 + (y – k)^2 = r^2\]

Answer 9

as your starting point.

Answer 10

sorry, I need to get off the Internet. 14 minutes seems sufficient time for you to respond beyond your original post. Good luck, happy studying.

Answer 11

im sorry haha. i got it:)