Find magnitude and direction of the vector I will medal and fan please thanks!

Question

hartnn · Answer

can you post the pic here?
it is too small to read..

Although, you can start:
we have x and y component.
$magnitude = \sqrt{x^2+y^2} \ direction = \angle \theta = tan^{-1}(\dfrac{y}{x})$

hartnn · Answer

ok, thats fine.
x = 75
y = 180

use the formula and try to get the magnitude and angle.
let me know if you get stuck.

hartnn · Answer

better :)

hartnn · Answer

good!

hartnn · Answer

$\tan^{-1}(y/x) = \tan^{-1}(180/75)$

which, when you use calculator, you get 67 degrees approx.

hartnn · Answer

and the direction is between south and east.

195mi, 67 south of east :)

anonymous · Answer

Ohh I now get it thank you

anonymous · Answer

Find cos t for this triangle wait one sec

hartnn · Answer

welcome ^_^

hartnn · Answer

ok

hartnn · Answer

which angle is t?

hartnn · Answer

cos t = side adjacent to t/hypotenuse

anonymous · Answer

Yea I post pic

anonymous · Answer

This one is confusing with the square roots

hartnn · Answer

you can post the pic here, using "Attach File" button

hartnn · Answer

adjacent side is 8,
hypotenuse = 16

8/16 = ..?

anonymous · Answer

I don't have that button 8/16 is cos T but answer choices are 1/2, 1/sqrt3, sqrr3/1, and swrt3/2

hartnn · Answer

16 = 2*8

hartnn · Answer

and everyone has the "Attach File" button.
Its on the left of "Post" button below

anonymous · Answer

I'm using mobile

hartnn · Answer

okk..

8/16 = 8/(2*8) 
8 cancels out.
1/2

anonymous · Answer

Oh 1/2 since 8 cancels out, thanks! And I have some couple of questions more

hartnn · Answer

post them as a new question, 
so that if i am unavailable, others can answer them :)

anonymous · Answer

Determine if triangles these are similar and if they are what postulate or theorem proves true similarity, profile pic is the diagram, thanks and ok:))