Question

Divide these polynomials.

(3x3 + x2 - 2x) (x2 + x)

A. 3x - 2x
B. 3x2 - 3x
C. 3x2 - x
D. 3x - 2

Answer 1

@dinamix

Answer 2

@KendrickLamar2014 hello

Answer 3

\[\frac{ 3x3+x2−2x }{ x2+x } = \frac{ 3x2+x−2 }{ x+1}\]

Answer 4

\[= \frac{ (3x−2)(x+1) }{ x+1 }\]

Answer 5

What does that equal? ^ @2kende

Answer 6

i dont understand that

Answer 7

Lets divide by parts, its really simple: \[\frac{ (3x-2)(x+1) }{ x+1 } = \frac{ (x+1) }{ x+1 } = ?\]

Answer 8

That cancels out ^ right?

Answer 9

what is all this /{[]/) stuff

Answer 10

Latex, can you see the numbers?

Answer 11

yes

Answer 12

Do you agree with me that (x+1)/x+1 cancels out?

Answer 13

i got 2.1 when u put it in the calculator

Answer 14

We dont need a calculator for this, only paper and a pencil/pen.

Answer 15

oh ok

Answer 16

can we take it little by little

Answer 17

how do i solve (x+1)/x+1

Answer 18

does x+1 = x1?

Answer 19

\[\frac{ (x+1) }{ x+1 } = 1\]

Answer 20

Since your dividing the same number, the answer would be 1

Answer 21

ohhhhhhhhhhhhh okk

Answer 22

how would i do it with 2 different numbers?

Answer 23

\[\frac{ 3x-2 }{ 1 } = ?\]

Answer 24

What would that equal ^

Answer 25

and where did u get (x+1)/x+1 from

Answer 26

can we stick wit the first step please until i understand it

Answer 27

Sure, the first step was divide: \[\frac{ 3x^3+x^2−2x }{ x^2+x }\]

Answer 28

OS is lagging for me, let me refresh the page.

Answer 29

i have to divide all that? how do i do that?

Answer 30

\[\frac{ x^2 }{ x^2 } = \frac{ x }{ x }\]

Answer 31

can u break this down , \[\frac{ 3x^3 }{ x^2 } = \frac{ 3x^2 }{ x}\] this is the part that is confusing me

Answer 32

Ok so, x^3/x^2 all that changes are the exponents.

Answer 33

why is the exponent 1 less?

Answer 34

We are diving all these numbers: \[\frac{ 3x^3+4x^2−4x }{ x^2+2x }\]

Answer 35

i wanna put all that in the calculator but u said we dont use one

Answer 36

No we just have to solve it out

Answer 37

thats the problem i dont know how to do that

Answer 38

answer D?

Answer 39

I dont have much time, but here is how you solve this problem. All you have to do is divide: \[\frac{ (3x^3+x^2-2x) }{ (x^2+x) }\]
\[= \frac{ (3x^2 + 4x-4) }{ x+1 }\]
\[\frac{ (3x−2)(x+1) }{ x+1 }\]
\[= 3x-2\]

Answer 40

Yes, the answer is D