Cos and sin with Unit Circle
Here are the problems: 2: a) cos (-3pi/2) b) sin (-3pi/2) My Answer: a) 0 b) -1 4: a) cos (15pi/4) b) sin (15pi/4) My Answer: a) sqrt(2)/2 b) -sqrt(2)/2 6: a) cos (4pi/3) b) sin (4pi/3) MA: a) -1/2 b) -sqrt(3)/2 8: a) cos(300 DEGREES) b) sin (300 degrees) MA: a) sqrt(3)/2 b) -1/2 10: cos (-360030 degrees) b) sin (360030 degrees) MA: -sqrt(2)/2 b) sqrt(2)/2
@FortyTheRapper
4 and 6 and 10 look good, I would recheck 2 and 8
Okay, I'll do that now
Wait 2 is right
So I should redo 8?
Right, your signs are right. It's just the values
Okay...one minute
I think I went wrong somewhere still 300 - 180 takes me to pi, then another 90 takes me to 270 degrees, another 30 degrees takes me to pi/6 ( in fourth quadrant) which is sqrt3/2, -1/2. Where did I mess up?
The first and third quadrants start with pi/6 The second and fourth quadrants start with pi/3 It's kinda like reflecting one side of the circle across the x (or y) axis
Oh. So it takes me to pi/3 which is (1/2, - sqrt(3)/2)?
Correct
Hmm, okay. I'll have to remember the reflection part. Can you help me with #9? cos (360045 degrees) b) sin (360045 degrees) I got cos right, but not sin
What were your answers?
a) sqrt(2)/2 b) -sqrt(2)@
So 360,045 Would you agree 360 can go into 360,000 evenly?
Yes,
Alright, so lets subtract that out \[360,045-360,000 = 45\] So now were just looking at Sin(45 degrees)
Right. Since it goes in there evenly, we're back at the 2pi side? So we're in the first quadrant?
Correct, at 360,000 we've made (I think 1,000) complete circles. We have 45 left, so we start at 0 degrees again
Ohh. Okay. That makes sense, so we have (sqrt(2)/2, sqrt(2)/2)
Correct!, since we landed in the first quadrant and x, y are both positive
Whoo! I see where I had gone wrong, thank you!
You're welcome!
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