Question

Medal for Geometry help.

Answer 1

@surjithayer

Answer 2

@daniel.ohearn1

Answer 3

didn't I just show u this yesterday

Answer 4

your method was incorrect, sorry.

Answer 5

after a rotation of 90 degrees, we have a coordinate change, like below:
\[\left( {x,y} \right) \to \left( {y, - x} \right)\]
for example, the new coordinates of \(T=(3,-1)\), are:
\((-1,-3)\)

Answer 6

please write the new coordinates of other points, using my rule above

Answer 7

X= (0,0)
M= (-1,-2) ----> (-2,-1)

Answer 8

Q= (1,-3)

Answer 9

I got this:
\(Q'=(3,1)\)

Answer 10

sorry, I have made an error, here is the right equation:
\[\left( {x,y} \right) \to \left( { - y,x} \right)\]

Answer 11

\[\left( {3, - 1} \right) \to \left( {1,3} \right) = T'\]

Answer 12

x=0,-3

Answer 13

please wait a moment, I have to review my equations @shaleiah

Answer 14

This might help http://www.regentsprep.org/regents/math/geometry/GT4/Rotate.htm

Answer 15

but looks like you got it, then?

Answer 16

the rule:
\[\left( {x,y} \right) \to \left( { - y,x} \right)\]
is correct!
so we have the subsequent images:
\[\begin{gathered}
\left( {3, - 1} \right) \to \left( {1,3} \right) = T' \hfill \\
\left( {0, - 3} \right) \to \left( {3,0} \right) = X' \hfill \\
\left( { - 2, - 1} \right) \to \left( {1, - 2} \right) = M' \hfill \\
\left( { - 1,3} \right) \to \left( { - 3, - 1} \right) = Q' \hfill \\
\end{gathered} \]

Answer 17

\[\left( {3, - 1} \right) \to \left( {1,3} \right) = T'\]
\[\left( {0, - 3} \right) \to \left( {3,0} \right) = X'\]
\[\left( { - 2, - 1} \right) \to \left( {1, - 2} \right) = M'\]
\[\left( { - 1,3} \right) \to \left( { - 3, - 1} \right) = Q'\]

Answer 18

@Michele_Laino

Answer 19

Omg, I got it :D

Answer 20

it is wrong, please look at my images above

Answer 21

are you sure?

Answer 22

yes!
for example, we have:
\[\left( {0, - 3} \right) \to \left( {3,0} \right) = X'\]
nevertheless it is different in the drawing

Answer 23

\(X_1=(0,3)\) is wrong

Answer 24

Alright, im going to re-graph the points.

Answer 25

please we have:
\[\left( {1,3} \right) = T'\]
whereas \(T_1=(3,1) \neq T'\)

Answer 26

okay, I understand.

Answer 27

please connect T1 wit Q1 directly

Answer 28

with*