Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (skittles_for_life6422):

Is my answer correct??? WILL GIVE MEDAL AND FAN!!!!!

OpenStudy (skittles_for_life6422):

The general equation of a plane is Ax + By + Cz = D, where A, B, C, and D are real numbers and A is nonnegative. Find the equation of the plane containing the points (3, 0, 0), (0, 8, 0), and (0, 0, 6). Show each step of your process. Then graph the plane. Answer: (2, 0, 0) -> 2A + 0 + 0 = D -> 2A = D -> A = D/2 (0, 6, 0) -> 0 + 6B + 0 = D -> 6B = D -> B = D/6 (0, 0, 5) -> 0 + 0 + 5C = D -> 5C = D -> C = D/5 plugging this back into the equation: (D/2)x + (D/6)y + (D/5)z = D [then divide through by D] (1/2)x + (1/6)y + (1/5)z = 1 and since we have to have integer coefficients, multiply through by 30 Equation: 15x + 5y + 6z = 30

OpenStudy (skittles_for_life6422):

OpenStudy (skittles_for_life6422):

Could check my answer @TheSmartOne

TheSmartOne (thesmartone):

You plugged in points that weren't even given to you...?

TheSmartOne (thesmartone):

Other than that, the process is correct.

OpenStudy (skittles_for_life6422):

really

OpenStudy (skittles_for_life6422):

then how is it suppose to be put in

OpenStudy (skittles_for_life6422):

one sec I'm going to see if I can do it correctly

OpenStudy (skittles_for_life6422):

(3, 0, 0) -> 3A + 0 + 0 = D -> 3A = D -> A = D/3 (0, 8, 0) -> 0 + 8B + 0 = D -> 8B = D -> B = D/8 (0, 0, 6) -> 0 + 0 + 6C = D -> 6C = D -> C = D/6 @TheSmartOne now what

OpenStudy (skittles_for_life6422):

Can you help @imqwerty

TheSmartOne (thesmartone):

Plug it into the equation. And solve for D.

OpenStudy (skittles_for_life6422):

i not sure how to do that correctly

TheSmartOne (thesmartone):

Oh wait, we don't solve for d. We divide by d and get an equation which is our anseer.

OpenStudy (skittles_for_life6422):

so how do you do that correctly

TheSmartOne (thesmartone):

(d/3)x + (d/8)y + (d/6)z = d Divide both sides by d.

OpenStudy (skittles_for_life6422):

ok so how do i find d

OpenStudy (skittles_for_life6422):

(1/3)x + (1/8)y + (1/6)z = 1

OpenStudy (skittles_for_life6422):

@TheSmartOne where did you go???

OpenStudy (skittles_for_life6422):

(x/3)+ (y /8)+ (z/6)= 1

OpenStudy (skittles_for_life6422):

now i need to find integer coefficients

OpenStudy (skittles_for_life6422):

does 2 work

TheSmartOne (thesmartone):

Now, multiply both sides by 24.

OpenStudy (skittles_for_life6422):

24? how did you get that?

OpenStudy (skittles_for_life6422):

(x/72)+ (y /192)+ (z/144)= 24

OpenStudy (skittles_for_life6422):

oh i see now 24 is the coefficient

OpenStudy (skittles_for_life6422):

did i multiply the sides correctly

TheSmartOne (thesmartone):

No, you divided by 24, not multiplied by 24.

TheSmartOne (thesmartone):

And 24 is the LCM of 3, 6, and 8. We want to get rid of the fractions so we multiply by 24.

OpenStudy (skittles_for_life6422):

so how is suppose to look like

TheSmartOne (thesmartone):

Like an equation

OpenStudy (skittles_for_life6422):

could plz help me do it I forgot how to do that:(

TheSmartOne (thesmartone):

24* (x/3 + y/8 + z/6) = 1 * 24 Simplify it.

OpenStudy (skittles_for_life6422):

8x+3y+4z=24

OpenStudy (skittles_for_life6422):

I get it now!!!

OpenStudy (skittles_for_life6422):

so now i have to graph it. i show it to you after im done

OpenStudy (skittles_for_life6422):

is this correct @TheSmartOne

TheSmartOne (thesmartone):

I'm not sure how to graph this @skittles_for_life6422

OpenStudy (skittles_for_life6422):

oh its a three-dimensional graph

TheSmartOne (thesmartone):

I know, that's why I don't know how to do it :p @skittles_for_life6422

OpenStudy (skittles_for_life6422):

thats ok thanks you soo much for all your help

TheSmartOne (thesmartone):

Anytime! @skittles_for_life6422

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!