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I need some help to calculate the molarity of the Hydrochloric acid in the flask. My values are 16 mL NaOH in the HNO3 flask, 20 mL HNO3 in the flask, and a pH around 8.2
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moles of solute per 1 liter solution
So 20 ml/16 ml for a M of 1.25?
The exact question is "Calculate the molarity of the Hydrochloric acid in the flask."
Trial 1 Trial 2 Trial 3 Initial volume of NaOH in buret 50.0 mL 49.9 mL 50.0 mL "Volume of HCl in flask " 20.0 mL 22.0 mL 39.1 mL Volume of NaOH remaining 34.0 mL 30.0 mL 32.4 mL
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