medal and fan!
we have to draw, these lines: \(y=3x+10\) and \[y = - \frac{{3x}}{4} - 1\]
yes! so the region involved, is the dark region
now, please you have to locate the point \((8,10)\)
what about partA
for part A, we can say this: "The solution region, is the region of all points \((x,y)\), whose y-coordinate, is Greater than \(3x+10\) and less than \( - \frac{{3x}}{4} - 1\)"
the points of the two lines \(don't\) belong to the solution region
okay
so now you need me to find the coordinates 8,10
now, for part B, please draw the point \((8,10)\) and check if such point is inside or outside the solution region
okay give me a second please:)
ok!
as we can see, such point is located outside the solution region please substitute its coordinate into the first inequality: \(y>3x+10\) what do you get?
coordinates*
i dont understand
oh i think i get it let me see if it works
hint: x=8, and y=10 so after substitution, we get: \[10 > \left( {3 \times 8} \right) + 10\] please simplify the right side
hint: what is \((3 \times 8)+10=...\)
hold on please im not very fast when i comes to math:)
ok!
x=30?
noooo
i did it wrong
I got this \((3 \times 8)+10=24+10=34\), am I right?
34 yep!
ok! So we got this statement: \(10>34\) is it true or false?
false
that's right! That is the Mathematical proof, that the point \((8,10)\) doesn't belong to the solution region
okay so the hole thing would be Part A: The solution region, is the region of all points (x,y), whose y-coordinate, is Greater than 3x+10 and less than −3x4−1" PartB: The point is located outside the solution region please substitute its coordinate into the first inequality: y>3x+10 =34 So we got this statement: 10>34 = false That is the Mathematical proof, that the point (8,10) doesn't belong to the solution region.
that's right!
please make sure to attach the graph of the solution region
okay thank you so much! do you mind checking two more of my questions to make sure that they are right?
ok!
i will post a new question
ok!
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