Question

I need help rn

Suppose that
Rx
is a polynomial of degree
9
whose coefficients are real numbers.
Also, suppose that
Rx
has the following zeros.
5i
,
+−4i
Answer the following.
(a) Find another zero of
Rx
.
(b) What is the maximum number of real zeros that
Rx
can have?
(c) What is the maximum number of nonreal zeros that
Rx
can have?

Answer 1

medal me

Answer 2

a) Other zeros of R(x) are complex conjugates of those listed: −4+5i, 1+i, 4i

b) Since R(x) has at least 6 complex non-real zeros,
maximum number of real zeros = 3

c) Non-real zeros come in complex conjugate pairs, since R(x) has real coefficients
so maximum number of non-real zeros = 8

Answer 3

Polynomial has a degree of 9.
5i, -4+i.

answer a, b, c please

Answer 4

@jameshorton

Answer 5

it a

Answer 6

literally what. someone help me.

Answer 7

If a polynomial has degree 9, and they give me 5i and -4+i, i know that A is -4-i, and that b should be 5, i do not understand C.

Answer 8

PLEASE I HAVE 7 MINUTES
@FaiqRaees @umerlodhi @helpkay

Answer 9

A: True, but you didn't state that or otherwise point it out.
B: 1 or 3
C: 6

The only possibilities are

Complex: 4 Real: 3 Total: 7
Complex: 6 Real: 1 Total: 7

Answer 10

i dont understand how it's 6, shouldn't it be 9-4=5, 5 is odd, if i go to 4 it is even. @jameshorton

Answer 11

4 mins left

Answer 12

it a

Answer 13

what is "it a"

Answer 14

it was 8 for c for anyone who actually wants to get answers on this website. you're welcome