Question

So I need to know this one is correct as well:

Find the LCM of the monomials.

14ab, 21bc

14: 14, 28, 42
21: 21, 42

Then I put the LCM for the variables (ab, bc) which will be.. b?

Which leaves me with 42b as the LCM?

@kelsey.benton00

Answer 1

Absolutely (: Do you understand why?

Answer 2

Um, not really, can you explain it?

Answer 3

So it looks like you've got the LCM down, as far as the multiples of 14 and 21 go. When it comes to ab and bc, the two parts of the equation share only one variable: b. Because b goes into both monomials, it can also be considered an LCM. So since the LCM of 14 and 21 is 42, and they both share b, the LCM is 42b (:

Answer 4

Okay, I have one more, can you help me, I don't quite understand this one...

Answer 5

@kelsey.benton00

Answer 6

Sure, shoot.

Answer 7

\[r^2, 5rst\]

Answer 8

So like since there's not a number on both terms, what do I do?

Answer 9

There doesn't have to be a number, there just needs to be something they have in common. In this case, what is the only variable they have in common?

Answer 10

r?

Answer 11

Yep, so the answer would simply be, r. (:

Answer 12

Thank you so much.

Answer 13

Anytime :p