Suppose that a single card is drawn from the deck, its suit is recorded, and the card is returned and ten the deck is reshuffled . if this process is repeated four times , what is the probability that a spade card will be drawn at least once?
What is the probability of drawing a spade card in each draw?
A standard deck has 52 cards, of which 13 cards are spades. So what is the probability of drawing a spade?
@LCSmith6892 Are you there?
Yes I'm here. 1/4?
Since the probability is the same each time, you can use the binomial probability formula
I'm having trouble remembering how to do any of it, to be honest.
You need the formula for binomial probability
is that \[\left(\begin{matrix}n \\ k\end{matrix}\right) p ^{k}q ^{n-k}\]
Yes!
Can you give me a hint on how to enter the data? For some reason on my paper I had written P(A|b) as the formula.
That's an entirely different formula P(A|b), looks like conditional probability p is the probability, q is just 1-p. n is the number of trials, 4 in this case. "At least once" is the same thing as: 1 minus the probability of exactly zero times - which means k is zero. Find the probability using the formula, then subtract it from 1.
p is the probability that you found a few posts back
Thank you! This looks a lot more familiar now.
The probability of drawing a spade card is 1/4 on each of the 4 draws. The probability of not drawing a spade card on each of the 4 draws is 1 - 1/4 = 3/4. Therefore the probability of not drawing a spade card after 4 draws is: \[\large P(0\ spades\ after\ 4\ draws)=(\frac{3}{4})^{4}\]\ So the probability that a spade card will be drawn at least once is given by: \[\large P(1\ or\ more\ spade\ cards)=1-(\frac{3}{4})^{4}\]
That is very helpful, Kropot72! Thank you both so much.
You're welcome :)
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