Ask your own question, for FREE!
Mathematics 4 Online
OpenStudy (anonymous):

Suppose that a single card is drawn from the deck, its suit is recorded, and the card is returned and ten the deck is reshuffled . if this process is repeated four times , what is the probability that a spade card will be drawn at least once?

OpenStudy (kropot72):

What is the probability of drawing a spade card in each draw?

OpenStudy (kropot72):

A standard deck has 52 cards, of which 13 cards are spades. So what is the probability of drawing a spade?

OpenStudy (kropot72):

@LCSmith6892 Are you there?

OpenStudy (anonymous):

Yes I'm here. 1/4?

OpenStudy (agent0smith):

Since the probability is the same each time, you can use the binomial probability formula

OpenStudy (anonymous):

I'm having trouble remembering how to do any of it, to be honest.

OpenStudy (agent0smith):

You need the formula for binomial probability

OpenStudy (anonymous):

is that \[\left(\begin{matrix}n \\ k\end{matrix}\right) p ^{k}q ^{n-k}\]

OpenStudy (agent0smith):

Yes!

OpenStudy (anonymous):

Can you give me a hint on how to enter the data? For some reason on my paper I had written P(A|b) as the formula.

OpenStudy (agent0smith):

That's an entirely different formula P(A|b), looks like conditional probability p is the probability, q is just 1-p. n is the number of trials, 4 in this case. "At least once" is the same thing as: 1 minus the probability of exactly zero times - which means k is zero. Find the probability using the formula, then subtract it from 1.

OpenStudy (agent0smith):

p is the probability that you found a few posts back

OpenStudy (anonymous):

Thank you! This looks a lot more familiar now.

OpenStudy (kropot72):

The probability of drawing a spade card is 1/4 on each of the 4 draws. The probability of not drawing a spade card on each of the 4 draws is 1 - 1/4 = 3/4. Therefore the probability of not drawing a spade card after 4 draws is: \[\large P(0\ spades\ after\ 4\ draws)=(\frac{3}{4})^{4}\]\ So the probability that a spade card will be drawn at least once is given by: \[\large P(1\ or\ more\ spade\ cards)=1-(\frac{3}{4})^{4}\]

OpenStudy (anonymous):

That is very helpful, Kropot72! Thank you both so much.

OpenStudy (kropot72):

You're welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!